Answer:
probability that Shaun loses both games
Step-by-step explanation:
Games are independent, so we find each separate probability, and multiply them.
In a chess club the probability that Shaun will beat Mike is 3/8.
So 
probability that Shaun loses.
The probability that Shaun will beat Tim is 5/7 .
So 
probability that Shaun loses.
What is the probability that Shaun loses both games?
This is:
probability that Shaun loses both games
Answer:18.9 miles
1 inch=5.4
3.5 inches =3.5×5.4
=18.9miles
hope this helps
please like and mark as brainliest
Answer:
yes
Step-by-step explanation:
Answer:
Step-by-step explanation:
Start with h(t) = -16t^2 + initial height, which here is h(t) = -16t^2 + 1296. Set this = to zero, which corresponds to the object hitting the ground (h = 0):
0 = -16t^2 + 1296. Dividing all terms by -16, we get t^2 = 81, whose positive square root is 9. It takes 9 seconds for the object to hit the ground.
