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Arisa [49]
3 years ago
7

Which fraction has a terminating decimal as its decimal expansion?

Mathematics
2 answers:
Helen [10]3 years ago
6 0

Answer:

1/5

Step-by-step explanation:

alex41 [277]3 years ago
5 0
'One third' as a decimal is 1 ÷ 3 = 0.333333..... ⇒ The decimal is recurring

'One fifth' as decimal is 1 ÷ 5 = 0.2 ⇒ The decimal terminates at the tenth value

'One seventh'  as decimal 1 ÷ 7 = 0.142857142857.... ⇒ The decimal is recurring for every digit between 1 and 7

'One ninth' as decimal 1 ÷ 9 = 0.111111.... ⇒ The decimal is recurring 

Answer: one fifth
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Step-by-step explanation:

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Which statement is NOT true about Rational Numbers? *
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Answer:

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Step-by-step explanation:

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3 0
3 years ago
The hypotenuse of the right triangle is 5y inches long. The lengths of the legs are x + 8 and x + 3 inches. If the perimeter of
Zolol [24]

Answer: 35 inches.

Step-by-step explanation:

We know that:

hypotenuse = 5*y in

cathetus 1 = (x + 8) in

cathetus 2 = (x + 3) in

The perimeter of the triangle is 76 inches, then:

5*y + (x + 8) + (x + 3) = 76

5*y + 2*x + 13 = 76

We also know that the length of the hypotenuse minus the length of the shorter leg is 17 in.

The shorter leg is x + 3, then:

5*y - (x + 3) = 17

Then we have the equations:

5*y + 2*x + 11 = 76

5*y - (x + 3) = 17

With only these two we can solve the system, first we need to isolate one of the variables in one of the equations, i will isolate x in the second equation.

x = 5*y  - 3 - 17 = 5*y - 20

x = 5*y - 20

Now we can replace this in the other equation, we get:

5*y + 2*x + 11 = 76

5*y + 2*(5*y - 20) + 11 = 76

15*y - 40 + 13 = 76

15*y - 29 = 76

15*y = 76 + 29 = 105

and remember that the hypotenuse is equal to 5*y, then we want to get:

3*(5*y) = 105

5*y = 105/3 = 35

5*y = 35

Then te length of the hypotenuse is 35 inches.

6 0
3 years ago
At leslie's school the ratio of boys and girls is 11 to 12 at marks school the ratio of boys girls is 41 to 48 if both schools h
Softa [21]

Answer: B. There are more boys at Mark's school than at Leslie's school because the ratio 41 to 48 is greater than the ratio 11 to 12.

Step-by-step explanation:

Here are the options:

A There are more boys at Mark's school than at Leslie's school because the ratio 11 to 12 is greater than the ratio 41 to 48.

B. There are more boys at Mark's school than at Leslie's school because the ratio 41 to 48 is greater than the ratio 11 to 12.

C. There are more boys at Leslie's school than at Mark's school because the ratio 41 to 48 is greater than the ratio 11 to 12.

At leslie's school the ratio of boys and girls is 11 to 12. This implies that the fraction of boys in the school to total students will be:

= 11/(11 + 12) = 11/23 = 0.4783

At Marks school the ratio of boys to girls is 41 to 48. Thus implies that the fraction of boys in the school to total students will be:

= 41 / (41 + 48) = 41/85= 0.4824

Based on the calculation, we can deduce that there are more boys at Mark's school than at Leslie's school because the ratio 41 to 48 is greater than the ratio 11 to 12.

6 0
3 years ago
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