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mario62 [17]
3 years ago
7

What's the difference between linear-quadratic and quadratic-quadratic?

Mathematics
1 answer:
Gnesinka [82]3 years ago
8 0
A quadratic equation is only different from a linear equation in one respect:one or more of the figures is squared.The common form of a quadratic equation is ax2+bx+c=11
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A deep-sea diver dived off a boat to a depth of -45 feet. What is the absolute value that expresses the distance the diver went?
Vlad1618 [11]

45 feet.

Absolute value is the distance of a number from 0. Say 0 is the surface of the ocean, then the diver is 45 feet away from it. Either from above or below, they are the same distance away.

7 0
3 years ago
Express 233 base four<br>as a base six.​
ahrayia [7]

Answer:

twenty one

Step-by-step explanation:

hhdhhdiejdihgeideseheeeiidgriuduurhidid

3 0
3 years ago
Need to know what z is on angle theorem
Ivenika [448]
<u>Adjacent angles on a straight line = 180:</u>
x + x + 48 = 180
2x + 48 = 180
2x = 132
x = 66°

<u>Sum of angles in a triangle = 180:</u>
z = 180 - 66 - 90 
z = 24°

Answer: z = 24°


3 0
3 years ago
Read 2 more answers
Eleven members of the Middle School Math Club each paid the same amount for a guest speaker to talk about problem solving at the
Ilia_Sergeevich [38]
The correct answer for the question that is being presented above is this one: "<span>The missing digit is 3."</span>

The missing digit is represented by A  ⇒  $1A2, where A represents a whole number from 0 to 9.

Try substituting any number from 0 to 9 for A (the middle digit or tens place) , then divide by 11 members.

<span>Option 2:  A = 3  ⇒  $1 </span><span>3 </span>2
$ 132 ÷ 11 = $12

The only one-digit that gives a whole number quotient when it takes the place of tens digit in $1 __2  is<span> 3.</span><span>   Because $ 132 ÷ 11 = $ 12. (Option 2)</span>

The missing digit is 3.
6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B9x%7D%5E%7B2%7D%20-%20%7B%28x%7D%5E%7B2%7D%20-%204%29%20%7B%7D%5E%7B2%7D%20
Alenkinab [10]

Answer:

{ x^2+3x-4}

Step-by-step explanation:

Factor top and bottom.

The numerator is a difference of two squares, and the denominator is a quadratic.

\frac{ {9x}^{2} - {(x}^{2} - 4)^{2} }{4 + 3x - {x}^{2} }

= \frac{ (3x+x^2-4)(3x-x^2+4) }{(1+x)(4-x)}

= \frac{ (x-1)(x+4) (1+x)(4-x) }{(1+x)(4-x)}

If x does not equal -1 and does not equal 4, we can cancel the common factors in italics to give

= { (x-1)(x+4)}

= { x^2+3x-4}

3 0
3 years ago
Read 2 more answers
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