<span><span><span><span>−<span>6x</span></span>+5</span>+<span>12x</span></span>−6 </span><span>=<span><span><span><span><span>−<span>6x</span></span>+5</span>+<span>12x</span></span>+</span>−<span>6
</span></span></span><span>=<span><span><span><span>−<span>6x</span></span>+5</span>+<span>12x</span></span>+<span>−6 </span></span></span><span>=<span><span>(<span><span>−<span>6x</span></span>+<span>12x</span></span>)</span>+<span>(<span>5+<span>−6</span></span>)</span></span></span><span>=<span><span>6x</span>+<span>−<span>1
</span></span></span></span><span><span>6x</span>−<span>1 is your answer.</span></span>
Radius of a wheel = 13 inch
= 1.08333 ft
circumference of a wheel = 2×pi×r^2
= 2 × (22/7) × 1.08333^2 ft
= 2 × (22/7) × 1.1736 ft
= (44/7)×1.1736 ft
= 51.6384/7 ft
= 7.3769142857 ft
distance covered in one minute = 37 × 60 ft/min
= 2220 ft/min
now, revolution per minute = 2220 / 7.3769142857
= 300.93884
therefore her wheels are making 300.93884 revolutions per minute
Answer:
592 in²
Step-by-step explanation:
Given
Length of the box L = 12 inches
Width W = 8 inches
height H = 10inches
Required
Surface Area of the box
Surface area of the rectangular boss = 2(LW + LH + WH)
Substitute the given values
Surface area = 2(12(8)+12(10)+8(10))
Surface Area = 2(96+120+80)
Surface Area = 2(96+200)
Surface area = 2(296)
Surface area = 592 in²
Hence 592 in² of wood would be needed by Mitchell to build the box
Answer:
42
Step-by-step explanation: