Answer:
Light is used by plants in a complex system that uses the light and several other resources to produce food. The more food= the more the plant grows, but too much food can be unhealthy for the plant. Some plants require more energy and others require less, this is because of the environment that they are in.
Explanation:
Answer:
(a) 133.33nm
(b) 600nm
(c) 7,600nm
Explanation:
The concentration of Y can be determined by using the formula:
where;
[L] = concentration of the binding ligand.
kd = 400 nm
Thus:
When Y = 0.25; we get :
0.25 (400 + [L]) = [L]
100 + 0.25[L] = [L]
100 = [L] - 0.25 [L]
100 = 0.75 [L]
[L] = 100/0.75
[L] = 133.33 nm
At, Y = 0.6
0.6 (400 + [L]) = [L]
240 + 0.6[L] = [L]
240 = [L] - 0.6 [L]
240 = 0.4 [L]
[L] = 240/0.4
[L] = 600 nm
At, Y = 0.95
0.95 (400 + [L]) = [L]
380 + 0.95[L] = [L]
380 = [L] - 0.95 [L]
380 = 0.05 [L]
[L] = 380/0.05
[L] = 7600 nm
Remember that density refers to the "mass per unit volume" of an object.
So, if an object had a mass of 100 grams and a volume of 100 milliliters, the density would be 100 grams / 100 ml.
In the question, water on the surface of the scale would add weight, so the mass of the object that you're weighing would appear to be heavier than it really is. If that happens, you'll incorrectly assume that the density is GREATER than it really is
As an example, suppose that there was 5 ml of water on the surface of the scale. Water has a density of 1 gram per milliliter (1 g/ml) so the water would add 5 grams to the object's weight. If we use the example above, the mass of the object would seem to be 105 grams, rather than 100 grams. So, you would calculate:
density = mass / volume
density = 105 grams / 100 ml
density = 1.05 g/ml
The effect on density would be that it would erroneously appear to be greater
Hope this helps!
Good luck
Answer:
The pressure is 0,97 atm
Explanation:
We apply Boyle Mariotte's Law, where for a certain mass of gas, at constant temperature, the pressure and volume vary inversely proportionally: P1x V1 = P2 x V2 P2= (P1 x V1)/V2
P2 = 1, 50 atm x 5, 00 L /7,74 L
P2= 0, 97 atm
When:
Fe(OH)3 ↔
Fe3+ + 3OH-so, each 1 mol Fe3+ → 3 mol OH-
and when [OH]
= 1.2 x 10^-5∴ [Fe3+] = (1.2 x 10^-5) / 3
= 4 x 10^-6when
Keq = [Fe3+][OH]^3 = (4 x 10^-6) (1.2 x 10^-5)^3
∴Keq = 6.9 x 10^-21