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yarga [219]
3 years ago
10

Sarah needs to replace part of the metal railing on her deck and wants the new railing to match the existing railing. However, s

he does not know what metal the railing is made from. Which is a property that she can use to identify the metal?
Chemistry
1 answer:
skelet666 [1.2K]3 years ago
8 0
There are many ways to test and identify metal. The easiest way is observing its color. Also how reflective it is. Other ways would be boiling point, melting point, density, or conductivity of the metal.
Hope This Helps and God Bless!
You might be interested in
The metallic radius of an aluminum atom is 143 pm. What is the volume of an aluminum atom in cubic meters?
Marina86 [1]

Answer:

6.61 × 10∧-29 m³

Explanation:

Given data:

Atomic radius= 143 pm = 143 × 10∧-12 m

volume = ?

Formula:

r = a/2√2

143 × 10∧-12 m = a/ 2√2

a= 143 × 10∧-12 m × 2√2

a= 404.4 × 10∧-12 m

where a is edge length, so we can calculate the volume by using following formula:

volume= a³

V= (404.4 × 10∧-12 m)³

v= 6.61 × 10∧-29 m³

8 0
3 years ago
A flexible container at an initial volume of 6.13 L contains 6.51 mol of gas. More gas is then added to the container until it r
aivan3 [116]

Answer:

the final mole of the flexible container = 12.92 moles

Explanation:

Given that :

initial volume of a flexible container = 6.13 L

initial mole of a flexible container = 6.51 mol

final volume of a flexible container = 18.3 L

final mole of a flexible container = ???

Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.

Therefore,

n= \dfrac{V_2*n_1}{V_1}

n= \dfrac{18.3*6.51}{6.13}

n = 19.43

n=n_1+n_2

19.43 = 6.51 + n₂

n₂ = 19.43 - 6.51

n₂ = 12.92 moles

Thus; the final mole of the flexible container = 12.92 moles

6 0
3 years ago
THIS HAS NOTHING TO DO WITH SCHOOL.
klio [65]

OMG yessss that is so cute she will totally accept

5 0
3 years ago
Read 2 more answers
Aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa.
Kaylis [27]

Answer:

abcabcabca

Explanation:

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4 0
3 years ago
What volume of O2 collected at 22.0 and 728 mmHg would be produce by the decomposition of 8.15 g KClO3?
adell [148]

Answer:

There is 2.52 L of O2 collected

Explanation:

Step 1: Data given:

Temperature = 22.0 °C

Pressure = 728 mmHg = 728 /760 = 0.958 atm

Mass of KClO3 = 8.15 grams

Molar mass of KClO3 = 122.55 g/mol

Step 2: The balanced equation

2KClO3(s) → 2KCl(s) + 3O2(g)

Step 3: Calculate moles of KClO3

Moles KClO3 = mass KClO3 / molar mass KClO3

Moles KClO3= 8.15 grams / 122.55 g/mol

Moles KClO3 = 0.0665 moles

Step 4: Calculate moles of O2

For 2 moles of KClO3 we'll have 2 moles of KCl and 3 moles of O2 produced

For 0.0665 moles of KClO3 we have 3/2 * 0.0665 = 0.09975 moles

Step 5: Calculate vlume of O2

p*V = n*R*T

V = (n*R*T)/p

⇒ with n = the number of moles O2 = 0.09975 moles

⇒ with R = the gas constant = 0.08206 L*atm/K*mol

⇒ with T = 22.0 °C = 273 +22 = 295 Kelvin

⇒ with p = 0.958 atm

V = (0.09975 * 0.08206 * 295) / 0.958

V = 2.52 L

There is 2.52 L of O2 collected

7 0
2 years ago
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