Let a=price of adult ticket
let c=price of a child's ticket
start out by writing the following system of equations:
3a+4c=132
2a+3c=94
then, multiply the first equation by 2, and the second equation by 3 to get the following system of equations:
6a+8c=264
6a+9c=282
subtract the like terms to get the following equation:
-c=-18
divide both sides by -1 to get rid of the negative to get the price of a child's ticket to be $18. to find the price of an adult ticket, pick one of the original equations to substitute the 18 in for c to find a. for example:
2a+3c=94
2a+3(18)=94
2a+54=94
-54 -54
2a=40
2 2
a=20
or if you decide to use the other equation:
3a+4c=132
3a+4(18)=132
3a+72=132
-72 -72
3a=60
3 3
a=20
either way, you still get an adults ticket to be $20 and a child's ticket to be $18.
Answer:
50
Step-by-step explanation:
p/5=10
Your main goal is to isolate p
p/5 = 10, in order to eliminate the 5, multiply 5 on both sides, since it's the inverse of division.
(5)p/5 = 10(5)
p=50
Lauren is on page 25. Since 75/15 is 5 that means she read fro 5 days. And they started at the same time so 5*5 is 25
Answer: x=3 ==> 1st option
Step-by-step explanation:
FH=FG+GH
18=4x+2x
6x=18
x=3 ==> 1st option
