Answer:
Option A. 416.1 g.
Explanation:
Data obtained from the question include the following:
Molarity = 1.743 M
Volume = 1.4957 L
Mass of CuSO4 =..?
Next, we shall determine mole of CuSO4 present in the solution.
This is illustrated below:
Molarity is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is expressed as:
Molarity = mole /Volume
With the above formula, we can obtain the mole CuSO4 present in the solution as follow:
Molarity = 1.743 M
Volume = 1.4957 L
Mole of CuSO4 =..?
Molarity = mole /Volume
1.743 = mole of CuSO4 /1.4957
Cross multiply
Mole of CuSO4 = 1.743 x 1.4957
Mole of CuSO4 = 2.607 moles
Finally, we shall convert 2.607 moles of CuSO4 to grams.
This can be obtained as follow:
Molar mass of CuSO4 = 63.55 + 32.06 + (16x4) = 159.61 g/m
Mole of CuSO4 = 2.607 moles
Mass of CuSO4 =..?
Mole = mass /molar mass
2.607 = mass of CuSO4 /159.61
Cross multiply
Mass of CuSO4 = 2.607 x 159.61
Mass of CuSO4 = 416.1 g
Therefore, 416.1 g of CuSO4 is needed to prepare the solution.
