Answer: 0.050M urea, 0.10M glucose, 0.2M sucrose, pure water
Explanation:
Vapor pressure refers to the ease with which a liquid substance is transformed into vapour. High vapour density implies that the liquid is easily transformed into gas. Pure water is expected to have the lowest vapour density since it is held by strong intermolecular forces in the liquid state. Urea is an organic liquid held by weak Van der Waals forces hence its extremely high vapor pressure.
Answer:
The factor that will change the volume of the diver's lungs upon reaching the surface is 4
Explanation:
Given data:
Pressure increases 1 atm = 101.325 kPa
34 ft = 10.3632 m
Depth of 102 ft = 31.0896 m
Question: What factor will the volume of the diver's lungs change upon arrival at the surface, V₂/V₁ = ?
The pressure at 31.0896 m:
The factor will the volume of the diver's lungs change upon arrival at the surface:
Answer:
Explanation:
Examples of compounds that contain only covalent bonds are methane (CH4), carbon monoxide (CO), and iodine monobromide (IBr). Covalent bonding between hydrogen atoms: Since each hydrogen atom has one electron, they are able to fill their outermost shells by sharing a pair of electrons through a covalent bond
To decrease the rate of the forward reaction you can do the following:
- decrease the concentration of the reactants
- increase the concentration of the products
- increase the pressure so the hydrogen gas will not be easily removed from the reaction
- decrease the temperature, number of collisions will decrease so the rate of the reaction will decrease
