All categories

2 years ago

5. How many grams of CuCl2 are required to make 75 mL of a 0.20M solution?

Chemistry

1 answer:

Effectus [21]2 years ago

5 0

35.8 cuc12 jk jk ok jk

You might be interested in

Write the electron configuration for a sodium cation with a charge of 1+

Dafna1 [17]

$1{s}^{2} 2 {s}^{2} 2 {p}^{6}$

or simply 2,8 it is isoelectronic with argon

4 0

3 years ago

For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coeffici

Brut [27]

Question:

For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coefficient for 0.124 b HCl solution if E=0.342 V at 298 K

Answer:

The mean activity coefficient for HCl solution is 0.78.

Explanation:

Activity coefficient is defined as the ratio of any chemical activity of any substance with its molar concentration. So in an electrochemical cell, we can write activity coefficient as γ. The equation for determining the mean activity coefficient is

$E=E_{0}-0.0514 \mathrm{V} \ln \gamma$

As we know that $E_{0}$ = 0.22 V and E = 0.342 V, the equation will become

$0.342 V+0.0514 V \ln (0.124)=0.22 V-0.0514 V \ln \gamma$

$0.342 V-0.222 V=-0.0514 V(\ln \gamma+\ln 0.124)$

$0.12 \mathrm{V}=-0.0514 \mathrm{V}(\ln \gamma+\ln 0.124)$

$\frac{0.12}{0.0514}=-\ln (0.124 \gamma)$

$-2.3346=\ln (0.124 \gamma)$

$e^{-2.3346}=0.124 \gamma$

$0.0968=0.124 \gamma$

$\gamma=\frac{0.0968}{0.124}=0.78$

So, the mean activity coefficient is 0.78.

6 0

3 years ago

What is the pH of a solution with a [H+] of 1.0 x 10-4 M?

MaRussiya [10]

PH = -log [H+]
pH = -log (1.0x10^-4) = -(-4) = 4 or A

4 0

3 years ago

A metallic bond can exist between atoms that have low ionization energies and

zavuch27 [327]

Answer: The elements that have the lowest electronegativity are the VIII A elements or noble gases. These elements have a theoretical electronegativity of zero. These elements are stable in their electron configuration there is not force moving the noble gases to gain any electrons.

Explanation:

7 0

2 years ago

The Sun heats land and water, how is this related to wind and ocean currents?

Yuki888 [10]

Answer:

"The sun warms up parts of the oceans. Warm waters rise just like warm air rises. So, as the warmer ocean waters begin to rise in a particular area, the cooler ocean waters from a different area will move in to replace the warmer ocean waters, and this creates our ocean currents."

Explanation:

Hope this is helpful :)

8 0

2 years ago