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Paladinen [302]
3 years ago
10

If 8cm^3 of H2 reacts with an excess of Cl2, calculate how much of the HCL(g) is produced.

Chemistry
1 answer:
Rom4ik [11]3 years ago
8 0
First, we need the balanced equation: H₂ + Cl₂ ---> 2HCl

since not much information is given, I am assuming we are at STP and that 22.4 Liters= 1 mol

1) let's convert the volume to moles using the molar volume of a gas. also we need to convert the cm₃ to mL, then to Liters.

8 cm³ (1 ml/ 1 cm³)(1 L/ 1000 mL) (1 mol/ 22.4 Liters)= 3.6x10⁻⁴ moles of H₂

2) let's use the mole ratio of the balanced equation to convert moles of H₂ to moles of HCl

3.6x10⁻⁴ mol H₂ (2 mol HCl/ 1 mol H₂)= 7.1x10⁻⁴ mol HCl

3) lastly, we convert the moles of HCl to grams using the molar mass.

molar mass of HCl= 1.01 + 35.5= 36.51 g/mol

7.1x10⁻⁴ mol HCl (36.51 g/mol)=<span> 0.026 grams HCl</span>
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John dalton postulated several statements about the atom. which statement did he NOT state?
algol [13]

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The postulate of Dalton's atomic theory  that atom is indivisible particle and can not be subdivided into smaller particles was later changed because atom can be divided into neutrons, protons and electrons.

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7 0
3 years ago
Good day pleases help
klemol [59]
I can’t see the choices can you take another picture of this assignment please so i can help you
6 0
3 years ago
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Humans have three types of cone cells in their eyes, which are responsible for color vision. Each type absorbs a certain part of
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Answer:

The frequency of this light is 6.98\times 10^{14} s^{-1}.

Explanation:

Wavelength of the light = \lambda = 430 nm=4.30\times 10^{-7} m

Speed of the light = c = = 3\times 10^8 m/s

Frequency of the light = \nu

\nu =\frac{c}{\lambda }

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The frequency of this light is 6.98\times 10^{14} s^{-1}.

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