when the product of six and the square of a number is increased by five times the number the result is four
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We are given the equations 3x+5y=-3 and x-5y=-5.
Both equations have a 5y term which allows us to easily solve the system by elimination. To do so we will add the equations together like a simple addition problem by adding the x terms together, the y terms together, and the integer answers together.
3x + 5y = -3
+x - 5y = -5
---------------
4x + 0y = -8
The y terms cancel out since one is positive and one is negative. Now we can solve for x.
4x = -8
x = -2
Now plug -2 in for x in one of the original equations to find y.
(-2) - 5y = -5
-5y = -3
y = 3/5
Our answer as an ordered pair is (2, 3/5)
Both equations have a 5y term which allows us to easily solve the system by elimination. To do so we will add the equations together like a simple addition problem by adding the x terms together, the y terms together, and the integer answers together.
3x + 5y = -3
+x - 5y = -5
---------------
4x + 0y = -8
The y terms cancel out since one is positive and one is negative. Now we can solve for x.
4x = -8
x = -2
Now plug -2 in for x in one of the original equations to find y.
(-2) - 5y = -5
-5y = -3
y = 3/5
Our answer as an ordered pair is (2, 3/5)