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aleksklad [387]
3 years ago
5

Someone help me please

Mathematics
1 answer:
Leviafan [203]3 years ago
5 0

Answer:

Look at the picture

Step-by-step explanation:

\log_ab=c\iff a^c=b\\\\\text{Therefore}\\\\f(x)=b^x\to y=b^x\\\\\text{find}\ f^{-1}(x).\ \text{Exchange}\ x\ \text{and}\ y\ \text{and solve for}\ y:\\\\b^y=x\qquad\text{logarithm iwth base b of both sides}\\\\\log_bb^y=\log_b(x)\qquad\text{use}\ \log_ab^m=m\log_ab\\\\y\log_bb=\log_b(x)\qquad\text{use}\ \log_aa=1\\\\y=\log_b(x)\\\\f^{-1}(x)=\log_b(x)\to g(x)=f^{-1}(x)\\\\\text{Then:}\ f(a)=b\to g(b)=a

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Solve the following equation for x. x = -2 x = 2 x = -17 x = -7 (x - 5)/2 = -6
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Step-by-step explanation:

x= -2,

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x=2,

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x= -17

(x - 5) / 2= -6

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x= -7,

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