When g(x) is divided by x + 4 the remainder is 0. Given g(x)=x^4+3x^3-6x+8 which conclusion about g(x) is true?

1 answer:

5 0

Check your textbook on the Remainder Theorem.

any divisor that yields a remainder of 0 from the dividend, IS a factor of the dividend.

namely, if x⁴+3x³-6x+8 ÷ x+4, gives a remainder of 0, then x+4 IS a factor of x⁴+3x³-6x+8.

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Step-by-step explanation:

Since, line contains the point (-8, 11) and has a y intercept of 5.

Therefore, line passes through the points (-8, 11) and (0, 5)

Equation of line in two point form is given as:

$\frac{y-y_1 }{y_1 - y_2 } = \frac{x-x_1 }{x_1 - x_2 } \\ \\ \therefore \: \frac{y-11 }{11 - 5 } = \frac{x-( - 11) }{ - 11 - 0 } \\ \\ \therefore \: \frac{y-11 }{6 } = \frac{x + 11 }{ - 11 } \\ \\ \therefore \: - 11(y-11 )=6 (x + 11) \\ \\ \therefore \: - 11y + 121=6 x + 66 \\ \\ \therefore \: 0=6 x + 11y + 66 - 121 \\ \\ \red{ \boxed{\therefore \: 6 x + 11y - 55 = 0}}$

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Answer:

Step-by-step explanation:

Let's solve your equation step-by-step.

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Step 1: Flip the equation.

b−6=−19

Step 2: Add 6 to both sides.

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