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3 years ago

How can you determine the domain and range of function.

Mathematics

2 answers:

Alecsey [184]3 years ago

8 0

<u>Answer and explanation:</u>

The set of all possible values of x that will make the function work, giving an output of real y values is said to be the domain of a function.

The domain of a function is determined by looking for the values of the independent variable (which is usually x) that are allowed to use.

While the complete set of all possible output values of the dependent variable (usually y), when we substitute the x values is called the range.

Range can be determined by the spread of the possible y-values (minimum y-value to maximum y-value).

Mice21 [21]3 years ago

4 0

Answer:

The domain of a function is the complete set of possible values of the independent variable.

In plain English, this definition means:

The domain is the set of all possible x-values which will make the function "work", and will output real y-values.

When finding the domain, remember:

The denominator (bottom) of a fraction cannot be zero

The number under a square root sign must be positive in this section

Step-by-step explanation:

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Algebra 1 Assignment! Help needed as soon as possible! thanks so much to whoever helps! have a nice day

mezya [45]

Answer:

Step-by-step explanation:

go-kart = Gk

Head sock = Hs (what? a sock in the head? :/ what ?? )

Laser tag = Lt

Eq 1 ) Gk + Hs + Lt = 33

Eq 2) 2Gk + Hs + 0Lt = 48

Eq 3) 2Gk + Hs + 2Lt =64

This is a system of equations w/ 3 unknowns and 3 equations so we can solve this. :)

subtract Eq 2 from Eq 3

2Gk +Hs +2Lt =64

-(2Gk +Hs +0Lt =48)

0Gk + 0 Hs +2Lt = 16

Lt =8

so one Laser tag game is 8 dollars.. good... now use 8 in Eq. 1 and 3 for Lt price

Eq 1a) Gk + Hs +8 =33 simplify

Eq 1b) Gk + Hs = 25

Eq 3a) 2Gk +Hs +2(8) = 64 simplify

Eq3b) 2Gk + Hs =48

subtract Eq 1b from Eq 3b

2Gk + Hs =48

-(Gk + Hs =25)

Gk = 23

so one Gk ride costs 23 dollars and plug this into Eq 1

23 + Hs + 8 = 33

Hs = 2

Question 1 ) Gk = 23 Hs = 2 Lt = 8

solve new systems, same as above but with the new prices

Eq 1r ) Gk + Hs + Lt = 18

Eq 2r) 2Gk + Hs + 0Lt = 29

Eq 3r) 2Gk + Hs + 2Lt =35

subtracting 2r from 3r we get 2Lt = 6 then Lt =3 for the new price

plug that into 1r and 3r

Eq 1br) Gk + Hs = 15

Eq 3br) 2Gk +Hs = 29

subtract 1br from 3br

Gk = 14

plug this into 1r

Hs =1

Question 2 ) Gk=14 Hs =1 Lt=3

Question 3) wants 2 Hs and 2 Lt

w/o coupon the activities cost 2 ( 2+8) = 20 dollars

but there is no coupon for 2 of each game

so no, don't buy a coupon.. just play at full price

Hustler side note.. buy two of the 18 coupons and sell the 2 Gk rides to your teacher for 15 dollars each, still a good deal to guarantee a good grade on your Home Work .. (30 total)...... and get your games for just 6 dollars... excellent deal for you :)

8 0

2 years ago

What is the name for a measurement of how two variables are related?

lorasvet [3.4K]

Answer:

correlation

Step-by-step explanation:

Correlation is a statistical technique that is used to measure and describe a relationship between two variables.

7 0

3 years ago

Read 2 more answers

I need help pleaseee stattt (11 points )

Harlamova29_29 [7]

Answer:

If you were to get a different piece of paper and trace the same shape and flip it over to the same position that one of them is in it will be the exact same measurements!

3 0

2 years ago

WILL GIVE BRAINLIEST, THANKS AND 5 STARS! PLEASE HELP! LOTS OF POINTS

irina [24]

First graph it

Maximum height is the y coordinate of vertex

(2,144)

Max height

144m

Time is the x coordinate of vertex

y is 0

$\\ \rm\Rrightarrow -16t^2+64t+80=0$

x intercepts are the solutions

(-1,0)U(5,0)

Take it positive

t=5s

put in function

y=-16(1)+64+80=-16+144=128ft

8 0

2 years ago

What percentage of the semi circle is shaded? <br>

mezya [45]

The percentage of the semicircle shaded section is approximately 23,606 %.

The percentage of the area of the semicircle is equal to the ratio of the semicircle area minus the half-cross area to the semicircle area. In other words, we have the following expression:

$r = \left(\frac{A_{s}-A_{h}}{A_{s}} \right)\times 100\,\%$

$r = \left(1-\frac{A_{h}}{A_{s}} \right)\times 100\,\%$ (1)

Where:

$A_{h}$ - Area of the half cross, in square centimeters.
$A_{s}$ - Area of the semicircle, in square centimeters.
$r$ - Percentage of the shaded section of the semicircle.

And the percentage of the shaded section is:

$r = \left[1-\frac{4 \cdot (2\,cm)^{2}+4\cdot \left(\frac{1}{2} \right)\cdot (2\,cm)^{2}}{0.5\cdot \pi\cdot (16\,cm^{2}+4\,cm^{2})} \right]\times 100$

$r \approx 23.606\,\%$

The percentage of the semicircle shaded section is approximately 23,606 %.

We kindly invite to check this question on percentages: brainly.com/question/15469506

3 0

2 years ago