Question

How do I solve this?

Answer 1

Answer:

x = - $\frac{7}{8}$

Step-by-step explanation:

given a quadratic in standard form

f(x) = ax² + bx + c (a ≠ 0 )

then the equation of the axis of symmetry is

x = - $\frac{b}{2a}$

f(x) = 4x² + 7x + 6 ← is in standard form

with a = 4 and b = 7

then equation of axis of symmetry is

x = - $\frac{7}{2(4)}$ = - $\frac{7}{8}$

Answer 2

Answer:

-7/8

Step-by-step explanation:

Quadratic formula is ax^2 + bx + c

In this case, x = -b/2a, which is -7/(2(4)) = -7/8