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3 years ago

Which expression is equivalent? −7(4x − 3) A) 28x + 21 B) 28x − 21 C) −28x + 21 D) −28x − 21

2 answers:

7 0

Use the rule of distributive property.
a × (b + c) = (a × b) + (a × c)

-7(4x - 3)

-28x + 21

hope this helps, God bless!

Mumz [18]3 years ago

7 0

Answer:

The equivalent expression is C) -28x + 21

Step-by-step explanation:

Let's consider the following expression.

-7 × (4x - 3)

In order to find the equivalent expression, we can use the distributive property of multiplication over subtraction.

-7 × 4x - (-7) × 3

- 28x - (-21)

- 28x + 21

The equivalent expression is

C) -28x + 21

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How is the sum expressed in sigma notation? 11 + 17 + 23 + 29 + 35 + 41

Ann [662]

<h3>The sum expressed in sigma notation is:</h3>

$11+17+23+29+35+41=\sum\limits_{i=1}^{6}5+6i$

Solution:

Given that,

11 + 17 + 23 + 29 + 35 + 41

We have to express the sum in sigma notation

Analyse the series

5 + 6(1) = 11

5 + 6(2) = 17

5 + 6(3) = 5 + 18 = 23

5 + 6(4) = 5 + 24 = 29

5 + 6(5) = 5 + 30 = 35

5 + 6(6) = 5 + 36 = 41

Thus the series goes on like this:

5 + 6(n) , where n = 1 to 6

This can be expressed in sigma notation as:

$11+17+23+29+35+41=\sum\limits_{n=1}^{6}5+6n$

We can expand the sigma notation and verify the results

$\sum\limits_{i=1}^{6}5+6i=(5+6(1))+(5+6(2))+(5+6(3))+(5+6(4))+(5+6(5))+(5+6(6))\\\\\\\sum\limits_{i=1}^{6}5+6i=(5+6)+(5+12)+(5+18)+(5+24)+(5+30)+(5+36)\\\\\\\sum\limits_{i=1}^{6}5+6i=11+17+23+29+35+41$

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3 years ago

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Assoli18 [71]

Wouldn't it be 12? because it is 3 6 9 ....

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Archy [21]

Answer:

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Step-by-step explanation:

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4 years ago

An artist plans a sculpture by stacking two cubes. Write an algebraic expression the artist can use to find the volume of the sc

vesna_86 [32]

Answer:

$V= 2x^3$

The volume is 128cm^3

Step-by-step explanation:

Given

$Cubes = 2$

$Sides = 4cm$

Required

Determine an expression for its volume

Find the volume

Volume of a cube is:

$Volume = x^3$

Where x represents the length of a side

So, volume of 2 cubes would be:

$V= x^3 + x^3$

$V= 2x^3$

Solving (b): Volume when x = 4

Substitute 3 for x in $V= 2x^3$

$V = 2 * 4^3$

$V = 2 * 64$

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Hence, the volume is 128cm^3

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The number of students in a room is an example of a continuous variable. true false

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