REALLY NEED HELP!!! PLZ

Mathematics

2 answers:

Alex777 [14]4 years ago

8 0

Whats the acctual question

mina [271]4 years ago

3 0

To find the improper question you multiply the denominator by the whole number then add the numerator
To find the mixed number divide the numerator by the denominator
I hope this helps

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How long will it take to administer 1000 cc at a drop factor of 15 drop/ml and a drip rate of 50 drop/min

gayaneshka [121]

First, we are going to determine the number of drops that needs to be administered by dividing the total volume by the volume per drop. Since, 1 cc (cm³) is equal to 1 mL then, 1000 cc is equal to 1000 mL.

n = (1000 mL)(15 drop/1 mL) = 15000 drops

Then, divide the number of drops by the number of drops per minute.

N = (15000 drops)/ (50 drop/min) = 300 mins

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3 years ago

The number of vibrations n n per second of a nylon guitar string varies directly with the square root of the tension T T and inv

emmasim [6.3K]

Answer: $T=40.96\ KgF$

Step-by-step explanation:

We know that:

$n$ : The number of vibrations per second of the nylon guitar string.

$T$ : Tension.

$L$ : The length of the string.

Since $n$ varies directly with the square root of the $T$ and inversely with $L$ , the equation has the following form:

$n=k*\frac{\sqrt{T} }{L}$

Where "k" is the constant of variation.

Knowing that when $n=15$ and $L=0.6$ , $T=256$ , we can find the value of "k":

$n=k*\frac{\sqrt{T} }{L}\\\\L*n=k\sqrt{T}\\\\\frac{L*n}{\sqrt{T}}=k\\\\k=\frac{(0.6)(15)}{\sqrt{256}}\\\\k=0.5625$

Finally, in order to find the tension when the length is 0.3 meters and the number of vibrations is 12, you need to substitute these values and the value of "k" into $n=k*\frac{\sqrt{T} }{L}$ and solve for $T$ :

$12=(0.5625)\frac{\sqrt{T} }{0.3}\\\\\frac{12(0.3)}{(0.5625)}=\sqrt{T}\\\\(6.4)^2=T\\\\T=40.96\ KgF$