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dezoksy [38]
3 years ago
15

Name two things that reduce friction

Physics
2 answers:
Natalka [10]3 years ago
8 0

Answer:

Reducing the normal force against the ground will reduce the amount of friction force, you can do this reducing the weight or mass of the object that you want to move.

Smoothing down the surface, for example, on a wet floor, the water fills some of the little imperfections in the ground, so the coefficient of dynamic friction in the ground is reduced.

Amiraneli [1.4K]3 years ago
6 0
<span>Make the surfaces smoother. Rough surfaces produce more friction and smooth surfaces reduce friction. ...Lubrication is another way to make a surface smoother. ...Make the object more streamlined. ...Reduce the forces acting on the surfaces. ...<span>Reduce the contact between the surfaces.

</span></span>
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How long does it take the baton to complete one spin
sweet [91]

The time it takes the baton to complete one spin will be 0.56 s. Option B is correct.

<h3>What is centripetal acceleration?</h3>

The acceleration needed to move a body in a curved way is understood as centripetal acceleration.

The direction of centripetal acceleration is always in the path of the center of the course. The total acceleration is the result of tangential and centripetal acceleration.

The entire question is;

"How long does it take the baton to complete one spin?

A twirler’s baton is 0.76 m long and spins around its center. The end of the baton has a centripetal acceleration of 47.8 m/s2.

a.0.31 s

b.0.56 s

c.4.3 s

d.70 s"

The given data in the problem;

Length of baton,L = 0.76 m

Centripetal acceleration,\rm F_c=47.8 \ m/s^2

The centripetal acceleration is found by;

a= \frac{4 \pi^2R}{T^2}

Substitute the given value:

\rm 47.82= \frac{4 \pi^2\times 0.38}{T^2} \\\\   47.82\times T^2 = 4(3.14)^2 \\\\T = 0.56 s

The time it takes the baton to complete one spin will be 0.56 s.

Hence option B is correct.

To learn more about centripetal acceleration, refer to the link;

brainly.com/question/17689540

#SPJ1

8 0
2 years ago
\There was a truck pulling a horse trailer. If the horse trailer weighted 150kg, went 250 miles, and the trucked used 20N to mak
mestny [16]

Answer:

a  = 0.13m/s²

Explanation:

Given parameters:

Weight of horse trailer  = 150kg

Distance covered  = 250miles

Force applied on trailer  = 20N

Unknown:

Acceleration of trailer = ?

Solution:

According to newton's second law of motion,"the acceleration of a body is directly proportional to the force on it and inversely proportional to the mass" .

          Mathematically;

                                    F  = m x a

 where f is the force

             m is the mass

               a is the acceleration

Input the parameters and solve;

                  20  = 150 x a

                      a  = 0.13m/s²

4 0
3 years ago
Which of the following is a part of the geocentric model?
Artyom0805 [142]

Answer:

All objects in the universe revolve around Earth.

7 0
3 years ago
A proton, moving west, enters a magnetic field of a certain strength. because of this magnetic field the proton curves upward. w
Bond [772]
Towards the south ........
6 0
4 years ago
When a scenario has tension force present, does that tension force also count as applied force? (also I assume tension force is
Pani-rosa [81]

Answer:

\underline{\boxed{B : C:D:E}}

Explanation:

\underline{ \boxed{ B}} :  \to \\ (the \: surface  \: exacts \: a \: force\: normal \: (at \: 90 \degree) \: on \:\to   A) \\  \underline{ \boxed{C }}:  \to \\ (dynamic \: friction \: force \: acts  \to \: on \: A \: as \: it \: slides) \\  \underline{ \boxed{D }} :  \to \\ (an \: anti - upward \: force \: acts \: on \to \:A \: preventing \: it \: from \: floating )  \\ \underline{ \boxed{ E }} :  \to  \\ (the \: weight \: of  \: B \: \: is \: applied \: to \to \: A)\\

7 0
3 years ago
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