Ask question

Ask question

All categories

3 years ago

5

A sinusoidal wave travels along a string. if the time for a particular point to move from maximum displacement to zero displacem

ent is 0.17 sec, what are the period and frequency? if the wavelength is 1.4 m what is the velocity?

1 answer:

Lisa [10]3 years ago

7 0

The time it takes for a point to reach 0 displacement from maximum displacement is $\frac{\pi}{2}$ of a cycle. Thus, one period ( $2\pi$ ) will take $T=0.17*4=0.68s$ .

The frequency is simply $f=\frac{1}{T}=\frac{1}{0.68}=1.47Hz$ .

The speed is given by: $v=f\lambda=1.47*1.4 = 2.06m/s$

You might be interested in

You know that there are 1609 meters in a mile. The number of feet in a mile is 5280. How many centimeters equals one inch

garik1379 [7]

<span>Hello there, and thank you for posting your question here on brainly.

<em><u /></em><span><em><u>Short answer: 2.54</u></em>
</span>
Why?

</span>No explanation needed.

Hope this helped you! ♥

4 0

3 years ago

Hey, what is antimatter

jenyasd209 [6]

A antimatter is particle physics, antimatter is a material composed of the antiparticle "partners" to the corresponding particles of ordinary matter. A particle and its antiparticle have the same mass as one another, but opposite electric charge and other quantum numbers.

5 0

3 years ago

Read 2 more answers

Each of 100 identical blocks sitting on a frictionless surface is connected to the next block by a massless string. The first bl

o-na [289]

Answer:

The tension in the string connecting block 50 to block 51 is 50 N.

Explanation:

Given that,

Number of block = 100

Force = 100 N

let m be the mass of each block.

We need to calculate the net force acting on the 100th block

Using second law of newton

$F=ma$

$100=100m\times a$

$ma=1\ N$

We need to calculate the tension in the string between blocks 99 and 100

Using formula of force

$F_{100-99}=ma$

$F_{100-99}=1$

We need to calculate the total number of masses attached to the string

Using formula for mass

$m'=(100-50)m$

$m'=50m$

We need to calculate the tension in the string connecting block 50 to block 51

Using formula of tension

$F_{50}=m'a$

Put the value into the formula

$F_{50}=50m\times a$

$F_{50}=50\times1$

$F_{50}=50\ N$

Hence, The tension in the string connecting block 50 to block 51 is 50 N.

8 0

3 years ago

How fast would the car need to go to double its kinetic energy?

boyakko [2]

Answer:

$v_{f} = \sqrt{2}\cdot v_{o}$

Explanation:

Let consider a car travelling at a speed $v_{o}$ . The ratio of final kinetic energy to initial kinetic energy:

$\frac{\frac{1}{2}\cdot m \cdot v^{2}_{f} }{\frac{1}{2}\cdot m \cdot v^{2}_{o}} = 2$

$\frac{v_{f}}{v_{o}} = \sqrt{2}$

The final speed is:

$v_{f} = \sqrt{2}\cdot v_{o}$

3 0

3 years ago

Read 2 more answers

Waves begin to "feel bottom" when the depth of water is

LekaFEV [45]

I think the correct answer would be one half the wavelength. Waves would "feel bottom" when the water is at the depth of 0.5 of the wavelength. "Feel bottom" is a term used to describe that the depth of water affects the wave properties. Hope this answers the question.

8 0

3 years ago

Read 2 more answers