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3 years ago

Which polygon is a base of the triangular

Mathematics

1 answer:

scZoUnD [109]3 years ago

7 0

Answer:

Polyhedron

Step-by-step explanation:

Polyhedron is a polygon with a 3-D base of a triangular pyramid shape.

Polyhedron also has a lateral face of triangular prism

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Which of the following is the vertex of the equation \large x^2-2x=-5 ?

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3 years ago

7. Find the sum or difference.<br> -2(d +1) + (6d +4)

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Answer:

Step-by-step explanation:

Sum

-2d + 1 + 6d + 4

Solving like terms

4d + 5

Difference

-2d + 1 - 6d - 4

-8d - 3

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3 years ago

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jeka57 [31]

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3 years ago

PLEASE HELP!

Wittaler [7]

Answer:

See below

Step-by-step explanation:

Use the formulae directly

For a cone, with base radius = r and height = h, here are the related formula

$\textrm{Slant height l} = \sqrt{r^2 + h^2}$ (1)

$\textrm{Lateral surface area} = \pi r l$

$\textrm {Base area} = \pi r^2$

$\textrm { Total Surface Area SA} = \textrm{Base Area + Lateral Area} = \pi r^2 + \pi rl = \pi r(r + l)$ (2)

$\textrm{Volume V = } (1/3) \pi r^2h$ (3)

Therefore directly plugging in the numbers in the above equations:

Note:

l = slant height in cm
SA = total surface area in sqcm
V = Volume in cubic cm

Figure(a)

r = 4, h = 8

$\textrm{l} = \sqrt{4^2 + 8^2} =\sqrt{80} = 8.944 \\\textrm{SA} = 4\pi(4 + 8.944) = 4\pi(12.944) = 162.66\\\textrm{V} = (1/3)\pi(4^2)(8) = 134.04$

Figure(b)

r = 7, h =15

$\textrm{l} = \sqrt{7^2 + 15^2} =\sqrt{274} = 16.55$

$\textrm{SA} = 7\pi(7 + 16.55) = 517.89$

Figure (c)

r = 5, l = 8

$h = \sqrt{l^2 - r^2} = \sqrt{8^2 - 5^2} = \sqrt{39} = 6.245\\SA = \textrm{SA} = 5\pi(5 + 8) = 204.2\\V = (1/3)\pi(5^2)(6.245) = 163.5$

6 0

2 years ago