Using the z-distribution, a sample size of 180 is needed for the estimate.
<h3>What is a z-distribution confidence interval?</h3>
The confidence interval is:
The margin of error is given by:
In which:
is the sample mean.
is the standard deviation for the population.
In this problem, we have a 98% confidence level, hence
, z is the value of Z that has a p-value of 
, so the critical value is z = 2.327.
The population standard deviation is of 
, and to find the sample size, we have to solve for n when M = 4.
Hence:
n = 179.03.
Rounding up, as a sample size of 179 would result in an error slightly above 4, a sample of 180 is needed.
More can be learned about the z-distribution at brainly.com/question/25890103
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Answer: 48 kilogramos de fruta
Step-by-step explanation:
Hola, para resolver este problema simplemente hay que sumar las cantidades de cada fruta:
Kilos de manzanas + kilos de mangos+ kilos de naranjas:
Matemáticamente hablando:
34+12+2 = 48 kg
Elena compro 48 kilogramos de fruta en total.
Si quedo alguna duda no dudes consultar con un comentario.
No, 1/3 is greater than 1/6.
1/3 converts to 2/6.
2/6 > 1/6
Step-by-step explanation:
3x - 4(4) = 65
3x - 16 = 65
3x = 81
x = 27
