All categories

3 years ago

Find the area of the figure. (Sides meet at right angles.)

Mathematics

2 answers:

kvasek [131]3 years ago

8 0

Answer:

19 yd²

Step-by-step explanation:

One way to find the solution is

Area of big rectangle =5* (3+2) =5*5 =25

Area of top small square = 2*2=4

Area of bottom small rectangle = 2*1 =2

Now put it all together:

Area of the figure = Area of big rectangle-Area of top small square-Area of bottom small rectangle= 25 -4 -2 = 21 -2 = 19 yd²

Alisiya [41]3 years ago

5 0

Answer:

the answer is 19yds squared

You might be interested in

A telephone pole has a wire to its top that is anchored to the ground. The distance from the bottom of the pole to the anchor po

Bumek [7]

Answer:

The height of the pole is 105ft,

Step-by-step explanation:

Let us call $h$ the height of the pole, then we know that the distance from the bottom of the pole to the anchor point is 49, or it is $h - 49$ .

The wire length $d$ is 14 ft longer than height $h$ , hence

$d= h+14$ .

Thus we get a right triangle with hypotenuse $d= y+14$ , perpendicular $h$ , and base $h-49$ ; therefore, the Pythagorean theorem gives

$(h-49)^2+h^2 = (h+14)^2$

which upon expanding we get:

$h^2-98h+2401 = h^2+28h+196$

further simplification gives

$h^2-126h+2205=0$ ,

which is a quadratic equation with solutions

$h =21ft\\h = 105ft.$

Since the first solution $h =21ft$ will give the triangle base length of $21ft-49ft = -28ft$ which is negative; therefore, we disregard it and pick the solution $h = 105ft$ .

Hence, the height of the pole is 105ft.

3 0

3 years ago

Standard form of a point that goes through-2,4 and the slope is -1/7

lesantik [10]

Answer:

Standard form of a line passing through (-2, 4) and having slope of -1/7 is x + 7y = 26

Solution:

Given that we need to determine standard form of a line that goes through (-2 , 4) and slope of the line is -1/7

Standard form of line passing through point ( a , b ) and having slope m is given by

(y – b) = m ( x – a) --------(1)

In our case given point is ( -2 , 4 ) and slope is -1/7 that means

a = -2 , b = 4 , m = -(1/7)

On substituting given value of a , b and m is equation (1) we get

$(y-4)=\left(-\frac{1}{7}\right)(x-(-2))$

$=>(y-4)=\left(-\frac{1}{7}\right)(x+2)$

=> 7( y - 4 ) = -x – 2

=> 7y + x = -2 + 28

=> x + 7y = 26

Hence standard form of a line passing through (-2,4) and having slope of –(1/7) is x + 7y = 26

8 0

3 years ago

A rock is launched from a cannon. After 1 second, the rock is 58 feet in the air; after 2 seconds, it is 112 feet in the air. Us

max2010maxim [7]

Answer:

Step-by-step explanation: This is the quadratic function:

h(x)=ax²+bx+c

We have two points:

(1,58)

(2,112)

Now, we calculate this quadratic funtion.

we assume that h(0)=0

Therefore:

a(0)²+b(0)+c=0

c=0

(1,58)

a(1)²+b(1)=58

a+b=58 (1)

(2,112)

a(2)²+b(2)=112

4a+2b=112

2a+b=56 (1)

With the equations (1) and (2) we make a system of equations:

a+b=58

2a+b=56

we can solve this system of equations by reduction method.

-(a+b=58)

2a+b=56

---------------------

a=-2

-2(a+b=58)

2a+b=56

-------------------

-b=-60 ⇒ b=60

The function is:

h(x)=ax²+bx+c

h(x)=-2x²+60x

Now find the height, in feet, of the rock after 10 seconds in the air.

h(10)=-2(10)²+60(10)

h(10)=-200+600=400

Answer: 400 ft.

8 0

3 years ago

-6(x-3) pls help me....

MariettaO [177]

Answer:

−6x+18

Step-by-step explanation:

-6(x-3)

(−6)(x+−3)

=(−6)(x)+(−6)(−3)

=−6x+18

4 0

3 years ago

Read 2 more answers

Angle m AOC=108° m AOB=3x+4° m BOC=8x-28° Find m AOB

Alex787 [66]

Hello from MrBillDoesMath!

Answer:

Discussion:

A diagram is always appreciated!

Assuming that

mAOC = mAOB + mBOC =>

108 = (3x + 4) + (8x - 28) => combine common terms

108 = (3x + 8x) + (4 - 28 ) =>

108 = 11x - 24 => add 24 to both sides

132 = 11x =>

x = 132/11 = 12

So mAOB = 3x + 4 = 3(12) + 4 = 36 + 4 = 40

Thank you,

MrB

4 0

3 years ago