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Andrei [34K]
3 years ago
11

What are the coordinates of the image of vertex R after a reflection across the y-axis?

Mathematics
2 answers:
Oxana [17]3 years ago
4 0

Answer:

(3,4)

Step-by-step explanation:

vfiekz [6]3 years ago
3 0
Consider any point P(x, y) in the coordinate axis.

The reflection of this point across the y-axis is the point P'(-x, y).

(x, y) and (-x, y) are the 'mirror' images of each other, with the y'axis as the 'mirror'.

For example the coordinates of the image of P(4, 13) after the reflection across the y-axis is P'(-4, 13)

or, if P(-5, -9), then P'(5, -9)


Answer: if coordinates of V are (h, k), coordinates of V' are (-h, k) 



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PLZ help with 6th math homework!
vitfil [10]
I'm not doing your math homework, this is to help you learn and pass your test :) I will however show you a trick. ask your self this... "What can i factor out of 4x that i can also factor out of 8, which this would be 4. Now what you do if you divide everything by 4

4x/4 = x
8/4 = 2

so 4(x+2) is 4x+8 fully factored, NOW to check, use the distributive property, Multiply 4 back into x+2
4*x = 4x
4*2 = 8
so 4(x+2) = 4x+8
3 0
3 years ago
Write the polar equation in rectangular form.
zhuklara [117]

Answer:

Step-by-step explanation:

The identities you need here are:

r=\sqrt{x^2+y^2}  and   r^2=x^2+y^2

You also need to know that

x = rcosθ  and

y = rsinθ

to get this done.

We have

r = 6 sin θ

Let's first multiply both sides by r (you'll always begin these this way; you'll see why in a second):

r² = 6r sin θ

Now let's replace r² with what it's equal to:

x² + y² = 6r sin θ

Now let's replace r sin θ with what it's equal to:

x² + y² = 6y

That looks like the beginnings of a circle.  Let's get everything on one side because I have a feeling we will be completing the square on this:

x^2+y^2-6y=0

Complete the square on the y-terms by taking half its linear term, squaring it and adding it to both sides.

The y linear term is 6.  Half of 6 is 3, and 3 squared is 9, so we add 9 in on both sides:

x^2+(y^2-6y+9)=9

In the process of completing the square, we created within that set of parenthesis a perfect square binomial:

x^2+(y-3)^2=9

And there's your circle!  Third choice down is the one you want.

Fun, huh?

5 0
3 years ago
2 + 1/3t = 1 + 1/4t<br> Please help me
navik [9.2K]

Answer:

<h3>r =-12</h3>

Step-by-step explanation:

2 + 1/3t = 1 + 1/4t\\\\2+\frac{1}{3}t=1+\frac{1}{4}t\\\\\mathrm{Subtract\:}2\mathrm{\:from\:both\:sides}\\2+\frac{1}{3}t-2=1+\frac{1}{4}t-2\\\\Simplify\\\frac{1}{3}t=\frac{1}{4}t-1\\\\\mathrm{Subtract\:}\frac{1}{4}t\mathrm{\:from\:both\:sides}\\\frac{1}{3}t-\frac{1}{4}t=\frac{1}{4}t-1-\frac{1}{4}t\\\\Simplify\\\frac{1}{12}t=-1\\\\\mathrm{Multiply\:both\:sides\:by\:}12\\12\times\frac{1}{12}t=12\left(-1\right)\\\\\\Simplify\\r =-12

8 0
3 years ago
Suppose C and D represent two different school populations where C &gt; D and C and D must be greater than 0. Whitch of the foll
In-s [12.5K]

Answer:

<em>A. (C+D)^2  is the largest expression</em>

Step-by-step explanation:

<u>Squaring Properties </u>

The square of a number N is shown as N^2 and is the product of N by itself, i.e.  

N^2=N*N

If N is positive and less than one, its square is less than N, i.e.

N^2

If N is greater than one, its square is greater than N

N^2>N, \ for\ N>1

We have the following information: C and D represent two different school populations, C > D, and C and D must be positive. We can safely assume C and D are also greater or equal than 1. Let's evaluate the following expressions to find out which is the largest

A. (C+D)^2

Expanding  

(C+D)^2=C^2+2CD+D^2

Is the sum of three positive quantities. This is the largest of all as we'll prove later

B. 2(C+D)

The extreme case is when C=2 and D=1 (recall C>D). It results:

2(C+D)=2(3)=6

The first expression will be

(3)^2=9

Any other combination of C and D will result smaller than the first option

C. C^2 + D^2

By comparing this with the first option, we see there are two equal terms, but A. has one additional term 2CD that makes it greater than C.

D. C^2 - D^2

The expression can be written as

(C+D)(C-D)

Comparing with A.

(C+D)^2=(C+D)(C+D)

The subtracting factor (C-D) makes this product smaller than A which has two adding factors.

Thus A. is the largest expression

7 0
3 years ago
A rectangular prism with a volume of 44 cubic units is filled with cubes with side lengths of 1/3 unit How many 1/3 unit cubes d
pickupchik [31]

Check the picture below.

so the volume of the smaller cube will just be (1/3)³.

how many of those cubes will take to fill up the larger cube?

namely

how many times does (1/3)³ go into 44?

\bf \left( \cfrac{1}{3} \right)^3\implies \cfrac{1^3}{3^3}\implies \cfrac{1}{27}\impliedby \textit{volume of the smaller cube} \\\\\\ 44\div \cfrac{1}{27}\implies \cfrac{44}{1}\div \cfrac{1}{27}\implies \cfrac{44}{1}\cdot \cfrac{27}{1}\implies 1188

7 0
3 years ago
Read 2 more answers
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