Answer:
51.84 cm
Step-by-step explanation:
Solution,
We have,
Area of the square= L²
According to question,
168 cm²= L²
√168 cm²= L²
√(12.96 cm)² = L
12.96 cm= L
Now,
We got,
Length of the square= 12.96 cm
By using the formula of perimeter of square,
We have,
Perimeter of square= 4L
=4×12.96 cm
=51.84 cm
Hence, the perimeter of square is 51.84 cm.
The types of correlation seen between positive correlation, negative correlation, or no correlation, in the variables is:
- a. Height of a person and how often he or she attends religious services. - No correlation
- (b.)Average property tax in a school district and salary of teachers - Positive correlation
- (c.)Weight of a person and shoe size. - Positive correlation
<h3>What is the correlation between property taxes and teacher salaries?</h3>
One of the main sources of funding for school districts is the property tax charged. This means that increased property taxes will lead to more money being available for teacher salaries which might then increase. There is therefore a positive correlation between the two.
The same is true for the weight of a person and shoe size. This is because the heavier a person is, the larger their shoe size according to research.
There is however no correlation between the height of a person and their attendance of religious services.
Find out more on positive correlation at brainly.com/question/17180881
#SPJ1
Answer:8-oz jar
First, we have to find out what is the unit rate of the 2-oz jar. $1.50÷2 is $.75.
Second, we have to find the unit rate of the 4-oz jar. $2.92÷4=$73.
Third, we have to find the unit rate of the 8-oz jar. $5.68=$.71.
Fourth, we have to find the unit rate of the 16-oz jar. The division for this one may be tricky. From dividing $11.62 by 16, is stopped at the 3rd number I got from dividing. I got $.726. This is not a value of cents and the value can't go in the thousandths place. So, I rounded .726. I got $.73. So $11.62÷16=$.73.
Lastly, you have to compare the amounts.
The lowest amount or better buy, is $.71 or 8-oz jar.
