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Marta_Voda [28]
3 years ago
14

Students are selling magnets. One magnet is $0.20, two magnets is $0.38, three magnets is $0.56, and four magnets is $0.74. If t

his pattern continues how much will six magnets cost?
Mathematics
1 answer:
satela [25.4K]3 years ago
3 0

Answer:

The cost of six magnets is $1.10

Step-by-step explanation:

The cost of 1 magnet  =  $ 0.20

Cost of 2 Magnets = $ 0.38

Now, the series of the cost of magnets is:

0.20 , 0.38, 0.56 , 0.74,...

Now, the above series forms an Arithmetic Progression as

0. 38  - 0. 20 = 0.18

and 0. 56  - 0. 38  =  0.18

Hence, the common difference of the series = 0.18

and first term of the series = 0.20

By , A.P  a(n) = a + (n-1) d

⇒a_6 = 0.20 + (6-1)(0.18)  \implies  a_6 = 0.20 + 5(0.18)

or, a(6) = 0.20  + 0.9 = 1.1

or,  the sixth term in the sequence is $1.1

Hence, the cost of six magnets is $1.1

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3 years ago
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Andrew is building a ramp for a snowboarding competition. The rules of the competition say that the height of the ramp must be 8
lara31 [8.8K]

Answer:

The length of the third piece of the ramp is;

D. 9.24 feet

Step-by-step explanation:

The given parameters are;

The height of the ramp = 8 feet

The angle between the piece that forms height and the base = 90°

The angle formed by the third piece connecting the height of the ramp to the furthest point and the 8 foot piece = 30°

Let 'y' represent the 8-foot piece forming the height, and let 'r' represent the third piece, by trigonometric ratio, we have;

cos(30^{\circ}) = \dfrac{y}{r}

Therefore, we get;

cos(30^{\circ}) = \dfrac{8}{r}

r = \dfrac{8 \ feet}{cos(30^{\circ})} = \dfrac{8 \ feet}{\dfrac{\sqrt{3} }{2}  }  = \dfrac{16 \cdot \sqrt{3} \ feet}{3}  \approx 9.24 \ feet

The length of the third piece, r ≈ 9.24 feet

3 0
3 years ago
The area of ABED is 49 square units. Given AGequals9 units and ACequals10 ​units, what fraction of the area of ACIG is represent
Mrac [35]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

A=b^{2}

where b is the length side of the square

we have

A=49\ units^2

substitute

49=b^{2}

b=7\ units

therefore

AB=BE=ED=AD=7\ units

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

A=(AC)(AG)

substitute the given values

A=(9)(10)=90\ units^2

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

A=(DE)(DG)

we have DE=7\ units

DG=AG-AD=9-7=2\ units

substituteA=(7)(2)=14\ units^2

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

A=(EF)(CF)

we have

EF=AC-AB=10-7=3\ units

CF=BE=7\ units

substitute

A=(3)(7)=21\ units^2

step 5

sum the shaded areas

14+21=35\ units^2

step 6

Divide the area of  of the shaded region by the area of ACIG

\frac{35}{90}

Simplify

Divide by 5 both numerator and denominator

\frac{7}{18}

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

5 0
3 years ago
Geometric Sequence♡<br><br>5, -2, 4/5<br><br>the common ratio was 2/5<br><br>find the 10th term​
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6 0
3 years ago
Please explain
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24-3x=-27
-24 -24
-3x=-51
— —
-3 -3

X=17
7 0
3 years ago
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