Hello,
Vertices are on a line parallele at ox (y=-3)
The hyperbola is horizontal.
Equation is (x-h)²/a²- (y-k)²/b²=1
Center =middle of the vertices=((-2+6)/2,-3)=(2,-3)
(h+a,k) = (6,-3)
(h-a,k)=(-2,-3)
==>k=-3 and 2h=4 ==>h=2
==>a=6-h=6-2=4 (semi-transverse axis)
Foci: (h+c,k) ,(h-c,k)
h=2 ==>c=8-2=6
c²=a²+b²==>b²=36-4²=20
Equation is:
Answer:
3
Step-by-step explanation:
(6 + 2 x 6)/(15 - 11 + 2)
(6 + 12)/(4 + 2)
18/6
3
Answer:
○ D. Yes, x = 12 is a zero of the polynomial.
The quotient is x + 22, and the remainder is 0.
Step-by-step explanation:
On a second thought, I knew something similar to that theorem because factoring them would determine if it has a remainder:
[x - 12][x + 22]
I am joyous to assist you anytime.
* I apologize for the previous answer I gave you.
In standard form, slope is always the negative of the x coefficient over the y coefficient.
If you dont want to have that memorized, you can use algebra to get the equation of the line into slope-intercept form (y=mx+b)
Set it equal to y
2x - 5y = 6
2x = 5y + 6
2x - 6 = 5y
(2/5)x - 6/5 = y
Now it is in slope intercept form. In slope intercept form, the coefficient multiplying with x is the slope of the line. Therefore, the slope equals 2/5.
Amount of money and checks could be one...