Answer:
10 Square Inches
Step-by-step explanation:
<u>Trapezoid</u>
Base =12 inches
Height =10 inches
Top side= 10 inches.
Area of a Trapezoid
Area of the Trapezoid=110 Square Inches
<u>Rectangle</u>
Base = 12 inches
Height =10 inches.
Area of a Rectangle=Base X Height
=12 X 10
=120 Square Inches
<u>Difference in Area between the two packages</u>
Difference=Area of Rectangle-Area of Trapezoid
=120-110
=10 Square Inches
Answer:
Step-by-step explanation:
In order to find the horizontal distance the ball travels, we need to know first how long it took to hit the ground. We will find that time in the y-dimension, and then use that time in the x-dimension, which is the dimension in question when we talk about horizontal distance. Here's what we know in the y-dimension:
a = -32 ft/s/s
v₀ = 0 (since the ball is being thrown straight out the window, the angle is 0 degrees, which translates to no upwards velocity at all)
Δx = -15 feet (negative because the ball lands 15 feet below the point from which it drops)
t = ?? sec.
The equation we will use is the one for displacement:
Δx = and filling in:
which simplifies down to
so
so
t = .968 sec (That is not the correct number of sig fig's but if I use the correct number, the answer doesn't come out to be one of the choices given. So I deviate from the rules a bit here out of necessity.)
Now we use that time in the x-dimension. Here's what we know in that dimension specifically:
a = 0 (acceleration in this dimension is always 0)
v₀ = 80 ft/sec
t = .968 sec
Δx = ?? feet
We use the equation for displacement again, and filling in what we know in this dimension:
Δx = and of course the portion of that after the plus sign goes to 0, leaving us with simply:
Δx = (80)(.968)
Δx = 77.46 feet
Answer: $2193
Step-by-step explanation:
v(x) = 32,500
Plug two and three in for x
v(2) = 32,500
v(2) = 32,500(.8464)
v(2) = 27,500
v(3) = 32,500
v(3) = 32,500(.778688)
v(3) = 25,307.36
Subtract v(3) from v(2)
27,500 - 25,307.36 = 2192.64
Round to the nearest dollar to get $2193