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SVETLANKA909090 [29]
3 years ago
11

Square root of 75 plus square root of 3

Mathematics
2 answers:
olya-2409 [2.1K]3 years ago
8 0
Answer:
6√3

Explanation:
Before we begin, remember the following:
\sqrt{a*b} = \sqrt{a}  *  \sqrt{b}
m \sqrt{a} + n \sqrt{a}  = (m+n) \sqrt{a}

Now, for the given:
75 can be written as 25*3
This means that:
\sqrt{75} = \sqrt{25*3}
Applying the above concept, we can find that:
\sqrt{75} = \sqrt{25*3} = \sqrt{25}  *  \sqrt{3}
Now, we know that:
√25 = 5 (we ignored the negative value)

This means that:
√75 = 5√3

Finally, we can compute the needed sum as follows:
√75 + √3 = 5√3 + √3 = 6√3

Hope this helps :)

lidiya [134]3 years ago
5 0
Your answer is: 10.3923048
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If the first of three consecutive integers is subtracted from 138, the result is the sum of the second and third. What are the i
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Step-by-step explanation:

Let First integer = n

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