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3 years ago

Please help AOB = ? BOC = ? BOD = ?

Mathematics

2 answers:

goldfiish [28.3K]3 years ago

7 0

From the diagram, we know that it is an angle that adds up to 360

So

x+4x+2x+10+5x+50=360

Gather like terms

12x+60=360

Move sixty to the other side as a negative number

12x=300

Divide both sirs by twelve

x is equal to 25

AOB is 2x+10

Sub x in 2*25+10

AOB is 60

BOC is 5x+50

5*25+50, which is 175

BOD is x+2x+10

Which is 3x+10

Sub x

3*25+10 which is 85

:)

evablogger [386]3 years ago

3 0

Answer: in between a and b it could be 12x

in between b and c it could be 55x

in between d and c it could be $4x^{o}$ than probably half that

in between b and c it could be $x^{o}$

or this

From the diagram, we know that it is an angle that adds up to 360

x+4x+2x+10+5x+50=360

Gather like terms

12x+60=360

Move sixty to the other side as a negative number

12x=300

Divide both sirs by twelve

x is equal to 25

AOB is 2x+10

Sub x in 2*25+10

AOB is 60

BOC is 5x+50

5*25+50, which is 175

BOD is x+2x+10

Which is 3x+10

Sub x

3*25+10 which is 85

Step-by-step explanation:

i think it could be like this

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Assume the random variable X is normally distributed with mean muequals50 and standard deviation sigmaequals7. Find the 87 th pe

serious [3.7K]

Answer:

57.885

Step-by-step explanation:

For such calculations a probability calculator is very helpful. The one in the attachment shows the 87th percentile to be 57.885.

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A table of the standard normal distribution will tell you the 87th percentile corresponds to a z-value of 1.12639. Then the X value is ...

X = Zσ +μ = 1.12639(7) +50 = 57.885

7 0

3 years ago

I NEED HELP ASAP PLS

xeze [42]

Answer:mot sire

Step-by-step explanation:

4 0

3 years ago

X²+y²-6x+14y-1=0 and please show your work so I can learn

Eva8 [605]

Hello there,

I hope you and your family are staying safe and healthy during this winter season.

$x^2 + y^2 -6x+14y-1=0$

We need to use the Quadratic Formula*

$x =\frac{-b+\sqrt{b^2}-4ac }{2a}$ , $\frac{-b-\sqrt{b^2} -4ac }{2a}$

Thus, given the problem:

$a = 1, b=-6, c=y^2+14y-1$

So now we just need to plug them in the Quadratic Formula*

$x=\frac{6+2\sqrt{(-6)^2-4(y^2+14y-1)} }{2}$ , $x=\frac{6-\sqrt{(-6)^2-4(y^2+14y-1)} }{2}$

As you can see, it is a mess right now. Therefore, we need to simplify it

$x=\frac{6+2\sqrt{10-y^2-14y} }{2}$ , $x = \frac{6-2\sqrt{10-y^2-14y} }{2}$

Now that's get us to the final solution:

$x=3+\sqrt{10-y^2-14y}$ , $x=3-\sqrt{10-y^2-14y}$

It is my pleasure to help students like you! If you have additional questions, please let me know.

Take care!

~Garebear

3 0

3 years ago

Given that f(x) = x^2 - 4x +1, find the value of m if f(m) = -3

iragen [17]

a. Answer: m = 2

Step-by-step explanation:

f(x) = x² - 4x + 1

f(m) = m² - 4m + 1 = -3

m² - 4m + 4 = 0

(m - 2)(m - 2) = 0

m = 2

***************************************************

b. Answer: k = 2 and k = 5

Step-by-step explanation:

f(x) = x² - 7x + 14

f(k) = k² - 7k + 14 = 4

k² - 7k + 10 = 0

(k - 2)(k - 5) = 0

k = 2 k = 5

3 0

3 years ago

Can you help me? Please

Anni [7]

9514 1404 393

Answer:

Step-by-step explanation:

For an even-index radical, ...

$\sqrt[n]{x^n}=|x|\qquad\text{n even}$

This lets us simplify the given expression as follows:

$\sqrt[4]{81x^6y^4}-|y|\sqrt[4]{x^6}-\sqrt[4]{16x^2}=\sqrt[4]{(3xy)^4x^2}-|y|\sqrt[4]{x^4x^2}-\sqrt[4]{2^4x^2}\\\\=3|xy|\sqrt[4]{x^2}-|xy|\sqrt[4]{x^2}-2\sqrt[4]{x^2}=\boxed{2|xy|\sqrt[4]{x^2}-2\sqrt[4]{x^2}}$

4 0

3 years ago