
is the equivalent to "five to the third power"
Answer:
1. 
2. not completely sure but i think its 
3.x
=
2
i
√
5
,
−
2
i
√
5
4.x
=
−
9
±
√
73
/2
5. Im not sure...
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Answer:
and the question is...
Step-by-step explanation:
Answer:
The answer is 364. There are 364 ways of choosing a recorder, a facilitator and a questioner froma club containing 14 members.
This is a Combination problem.
Combination is a branch of mathematics that deals with the problem relating to the number of iterations which allows one to select a sample of elements which we can term "<em>r</em>" from a collection or a group of distinct objects which we can name "<em>n</em>". The rules here are that replacements are not allowed and sample elements may be chosen in any order.
Step-by-step explanation:
Step I
The formula is given as

n (objects) = 14
r (sample) = 3
Step 2 - Insert Figures
C (14, 3) =
= 
= 
= 
= 364
Step 3
The total number of ways a recorder, a facilitator and a questioner can be chosen in a club containing 14 members therefore is 364.
Cheers!
Answer:
7
Let's solve your equation step-by-step.
5x−7+2−2x=−26
Step 1: Simplify both sides of the equation.
5x−7+2−2x=−26
5x+−7+2+−2x=−26
(5x+−2x)+(−7+2)=−26(Combine Like Terms)
3x+−5=−26
3x−5=−26
Step 2: Add 5 to both sides.
3x−5+5=−26+5
3x=−21
Step 3: Divide both sides by 3.
3x
3
=
−21
3
x=−7
Answer:
x=−7