Ask question

Ask question

All categories

3 years ago

14

Marita is cutting rolls of ribbon that are 3 feet long into 1/2- foot pieces. She needs fifteen 1/2- foot pieces for a project.

She has 3 rolls of ribbon. Does she have enough to cut 15 pieces? Explain.

1 answer:

kondaur [170]3 years ago

3 0

Answer: Yes

Step-by-step explanation:

3 * 2 = 6. So you can get 6 1/2 foot pieces out of 1 roll. She has 3 rolls. 6 * 3 = 18. 18 is more than 15.

You might be interested in

FASTTTTTTTTT PPPPPPPPPPPPPPLLLLLLLLLLLLLLLLZZZZZZZZZZZZZZZ

Deffense [45]

Answer:

(a) B

(b) $2

Step-by-step explanation:

(a) Let's say the cost of a ticket is t and the cost of popcorn is p. Then we can write the two equations from the table:

12t + 8p = 184

9t + 6p = 138

We need to solve this, so let's use elimination. Multiply the first equation by 3 and the second equation by 4:

3 * (12t + 8p = 184)

4 * (9t + 6p = 138)

We get:

36t + 24p = 552

36t + 24p = 552

Subtract the second from the first:

36t + 24p = 552

- 36t + 24p = 552

________________

0 = 0

Since we get down to 0 = 0, which is always true, we know that we cannot determine the cost of each ticket because there is more than one solution (infinitely many, actually). The answer is B.

(b) Our equation from this, if we still use t and p, is:

5t + 4p = 82

Now, just choose any of the two equations from above. Let's just pick 9t + 6p = 138. Now, we have the system:

5t + 4p = 82

9t + 6p = 138

To solve, let's use elimination again. Multiply the first equation by 6 and the second one by 4:

6 * (5t + 4p = 82)

4 * (9t + 6p = 138)

We get:

30t + 24p = 492

36t + 24p = 552

Subtract the second from the first:

36t + 24p = 552

- 30t + 24p = 492

________________

6t + 0p = 60

So, t = 60/6 = $10. Plug this back into any of the equations to solve for p:

5t + 4p = 82

5 * 10 + 4p = 82

50 + 4p = 82

4p = 32

p = 32/4 = $8

So the ticket costs 10 - 8 = $2 more dollars than the popcorn.

5 0

3 years ago

Read 2 more answers

The sum of two consecutive integers is -133 find the integers

Bess [88]

-133/2=-66.5

If we take the upper and lower round of that number we will get the 2 consecutive numbers that make -133.
Therefore the answer is -66 & -67.

8 0

3 years ago

What are the endpoint coordinates for the midsegment of △BCD that is parallel to BC?

natulia [17]

Answer:

<em>The endpoint coordinates for the mid-segment are: $(-2,-1)$ and $(1,0)$ </em>

Step-by-step explanation:

According to the given diagram, the coordinates of the vertices of $\triangle BCD$ are: $B(-3,1), C(3,3)$ and $D(-1,-3)$

Now, the endpoints of the mid-segment of $\triangle BCD$ which is parallel to $BC$ will be the mid-points of sides $BD$ and $CD$ .

<u>Formula for the coordinate of mid-point</u> : $(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2})$ , where $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ are two endpoints.

So, the mid-point of $BD$ will be: $(\frac{-3-1}{2},\frac{1-3}{2})=(\frac{-4}{2},\frac{-2}{2})=(-2,-1)$

and the mid-point of $CD$ will be: $(\frac{3-1}{2},\frac{3-3}{2})=(\frac{2}{2},\frac{0}{2})=(1,0)$

Thus, the endpoint coordinates for the mid-segment of $\triangle BCD$ that is parallel to $BC$ are $(-2,-1)$ and $(1,0)$

4 0

3 years ago

Read 2 more answers

A circle with radius of 4 cm sits inside a circle with radius of 11 cm.

kap26 [50]

The area of the shaded region = 330 sq cm

Step-by-step explanation:

Given,

The radius of small circle (r) = 4 cm

The radius of large circle (R) = 11 cm

To find the shaded region

Formula

The area of circle of radius r = π $r^{2}$ sq cm

So, The radius of the small circle = π× $4^{2}$ sq cm = 16π sq cm

The radius of the large circle = π× $11^{2}$ sq cm = 121π sq cm

Hence the area of the shaded region = 121π-16π sq cm

= 105π sq cm

= 105 × $\frac{22}{7}$ sq cm = 330 sq cm

5 0

3 years ago

Read 2 more answers

What value is missing from the table?

AleksandrR [38]

Answer:

12

Step-by-step explanation:

15/1.25 is 12

3 0

3 years ago