1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
irina [24]
3 years ago
14

Marita is cutting rolls of ribbon that are 3 feet long into 1/2- foot pieces. She needs fifteen 1/2- foot pieces for a project.

She has 3 rolls of ribbon. Does she have enough to cut 15 pieces? Explain.
Mathematics
1 answer:
kondaur [170]3 years ago
3 0

Answer: Yes

Step-by-step explanation:

3 * 2 = 6. So you can get 6 1/2 foot pieces out of 1 roll. She has 3 rolls. 6 * 3 = 18. 18 is more than 15.

You might be interested in
Find the following of each arc measure
Dimas [21]
ZW= 108
VW= 55
UY= 34
8 0
3 years ago
Each side of the hexagon is 1cm long. What is its perimeter?
Alex Ar [27]
It is 6cm
Because a hexagon has 6 sides and if each side is 1cm long then add 6 to 1
7 0
3 years ago
Read 2 more answers
Write the equation of a line with the x and y intecepts standard form
Lera25 [3.4K]
Standard form y =mx + b
8 0
3 years ago
Name the property illustrated (7+8)+9=7+(8+9)<br><br> I need help plz
Svetllana [295]

Answer:

i believe it is associative property

Step-by-step explanation:

hope this helps, sry if im wrong

3 0
2 years ago
Which equation could be used to find the zeros of the function f(x) = 6x2-11x-10 = 0 ? (x+2)(x-5) = 0 (3x+2)(2x-5) = 0 (x-10)
Alex Ar [27]

Answer:

(3x+2)(2x-5) = 0

Step-by-step explanation:

In the multiple choice options, all of the answers are in factored form. Factored from for quadratic equations are used to find the zeroes, when you equate each factor to 0.

Remember quadratic equations are in the form ax² + bx + c = 0.

Factor 6x² - 11x - 10 = 0:

I will use the <u>cross factors or "X"</u> method.

Write out the factors for "a" and "c" vertically (see diagram 1).

Test a pair of factors from "a" and a pair of factors from "c". Cross multiply them and add their products. If the sum of their products is "b", you found the factors.

The value of "b" is -11.

Example 1: (diagram 2)

I will try if the highlighted pairs of factors work. Multiply the pairs diagonally, which gives me "1" and "-60". The sum of "1" and "-60" is -59.

-59 is not -11; this is not the pair we want.

Example 2: (diagram 3)

Try another pair. Multiply 2*5=10 and 3*-2= -6. Add them together; -6 + 10 = 4.

4 is not -11; this is also wrong.

Example 3: (diagram 4)

Multiply 2*2=4 and 3*-5= -15.

Add the answers: 4 + (-15) = -11.

-11 is "b". Keep these factor pairs.

Find the factors: (diagram 5)

The factors are found by reading across the top and the bottom. Include "x" with the first factor.

(2x-5)(3x+2) = 0  or (3x+2)(2x-5) = 0

4 0
3 years ago
Other questions:
  • Mary got a piggy bank as a gift with X cents in it. If she saves Y cents each month for a year, how much money will she have in
    9·1 answer
  • HELP!!! Plz ?<br><br> Divide, and then round the answer to two decimal places: 0.2292713 ÷ 0.746
    15·1 answer
  • Need help pleasethank you
    8·1 answer
  • Approximate the square root of 44 to the nearest tenth
    8·2 answers
  • At a 20th high school reunion, all the classmates were asked the number of children they had. The probability of having a partic
    9·1 answer
  • A group of 5 friends spent a total of $18 on a bottle of juice and a package of dried fruit for each of them. Each juice cost $1
    8·2 answers
  • An auto mechanic converts a metric part to 0.492 in. The part comes only in fractional sizes given to the nearest 64th of an inc
    5·1 answer
  • Which pair of x and y values below are the solution to the simultaneous equations? x+2y=6<br> x-2y=2
    10·1 answer
  • The spinner below is spun, then a month of the year is randomly selected. Find the probability of P(unshaded, then a month that
    8·1 answer
  • The table shows the last holiday destination of 60 people
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!