Answer:
B
Step-by-step explanation:
when you solve B you get 15 and for all the other ones you get a non-terminating decimal
Answer:
![x_1=5\\x_2=-3](https://tex.z-dn.net/?f=x_1%3D5%5C%5Cx_2%3D-3)
Step-by-step explanation:
You have the following quadratic equation given in the problem:
![x^{2}-2x-3=12](https://tex.z-dn.net/?f=x%5E%7B2%7D-2x-3%3D12)
You must make the equation equal to zero, as following:
![x^{2}-2x-3-12=0](https://tex.z-dn.net/?f=x%5E%7B2%7D-2x-3-12%3D0)
Add like terms:
![x^{2}-2x-15=0](https://tex.z-dn.net/?f=x%5E%7B2%7D-2x-15%3D0)
Now, to factor the equation, you must find two numbers whose sum is -2 and whose product is -15. Therefore, you have:
![(x-5)(x+3)=0\\x_1=5\\x_2=-3](https://tex.z-dn.net/?f=%28x-5%29%28x%2B3%29%3D0%5C%5Cx_1%3D5%5C%5Cx_2%3D-3)
Answer:
hi
Step-by-step explanation:
Answer:
<em>The answers are for option (a) 0.2070 (b)0.3798 (c) 0.3938
</em>
Step-by-step explanation:
<em>Given:</em>
<em>Here Section 1 students = 20
</em>
<em>
Section 2 students = 30
</em>
<em>
Here there are 15 graded exam papers.
</em>
<em>
(a )Here Pr(10 are from second section) = ²⁰C₅ * ³⁰C₁₀/⁵⁰C₁₅= 0.2070
</em>
<em>
(b) Here if x is the number of students copies of section 2 out of 15 exam papers.
</em>
<em> here the distribution is hyper-geometric one, where N = 50, K = 30 ; n = 15
</em>
<em>Then,
</em>
<em>
Pr( x ≥ 10 ; 15; 30 ; 50) = 0.3798
</em>
<em>
(c) Here we have to find that at least 10 are from the same section that means if x ≥ 10 (at least 10 from section B) or x ≤ 5 (at least 10 from section 1)
</em>
<em>
so,
</em>
<em>
Pr(at least 10 of these are from the same section) = Pr(x ≤ 5 or x ≥ 10 ; 15 ; 30 ; 50) = Pr(x ≤ 5 ; 15 ; 30 ; 50) + Pr(x ≥ 10 ; 15 ; 30 ; 50) = 0.0140 + 0.3798 = 0.3938
</em>
<em>
Note : Here the given distribution is Hyper-geometric distribution
</em>
<em>
where f(x) = kCₓ)(N-K)C(n-x)/ NCK in that way all these above values can be calculated.</em>
Answer:
<u>239 students and 153 non-students attended to the school production of "Our Town"</u>
Step-by-step explanation:
1. Let's review the information provided to us to answer the question correctly:
Number of tickets of the school production sold = 392
Student ticket cost = US$ 3
Non-students ticket cost = US$ 5
Total collected = US$ 1,482
2. How many students and how many non-students attended?
For answering the question we will use the following equation:
x = Number of students that attended the school production
392 - x = Number of non-students that attended the school production
3x + (392 - x) * 5 = 1,482
3x + 1,960 - 5x = 1,482
-2x = 1.482 - 1,960
-2x = - 478
x = -478/-2
<u>x = 239 ⇒ 392 - 239 = 153</u>
<u>239 students and 153 non-students attended to the school production of "Our Town"</u>