GCF is a shared factor
14x^2 and 4xy share the greatest factor of 2x
A quadratic has the form ax^2+bx+c
To factor a quadratic you want to find two values, j and k, which satisfy two conditions...
j*k=a*c and j+k=b
In this case ac=-140 and b=4.
The only values possible are j=14 and k=-10
so jk=-140 and j+k=4 which are the conditions we needed to satisfy...
Now you remove the linear, or "b term", from the original equation and replace it with jx and kx... and in this case you will have:
-2h^2-14h+10h+70 now you can factor out the greatest common factor from the first pair of terms and the second pair of terms...
-2h(h+7)+10(h+7) which is equal to
(-2h+10)(h+7) and you can factor the first term again if you wish...
-2(h-5)(h+7)
Answer: I believe the answer is y= mx + b
Step-by-step explanation:
I think the first number is 2
Then 2 x 2 = 4 so there is a difference of 4 number
Then in between 6 and 14 there is a difference of 8 so 4 x 2 = 8
Then 16 so 8 x 2 = 16
So after 126 the number is 254
Answer:
I don't see a graph
Step-by-step explanation:
