Answer: 31.18
Step-by-step explanation:
The problem is focused on mainly the right triangle made up of points M, Q, and R. This problem can be solved with the base formula, <em>b</em> = <em>a</em> · tan(β) where <em>a</em> = the length of line MR, β = m∠MQR, and <em>b</em> is the unknown length of RQ.
Given:
RQ = 18 · tan(60°)
Point M is the midpoint of line PM and line MR. Since MP is equal to 18, MR has to be 18 as well. This means that the value of <em>a</em> is 18.
The vertex of ∠MQR is Q, which is 60°.
Step 1: Find the tangent of 60°
The tangent of 60° is √3
Step 2: Solve
RQ = 18 · √3
18 · √3 = 31.18
RQ is equal to 31.18
Are you sure you typed your equation correctly? Is the _ meant to be a division symbol?
Answer:
so he ran 84 miles and if you need 378.
Step-by-step explanation:
3*28=84miles
and then 84*4.5=378
Answer:
7/16
Approximately 0.44
Step by step explanation:
For the 1st student to arrive before 2nd student,
* the probability that he(1st student)to arrive during 3/4 hrs = 3/4
*Then he(1st student) will need to wait for 1/4 hrs
*The probability that he(1st student) arrive during the last 1/4 hrs = 1/4
*Then he(1st student) waits for average of 1/8 hrs (1/4 + 1/4)=1/8
*The total time he(1st student) wait = (3/4 ×1/4) +(1/4× 1/8) = 7/32
*For 1st and 2nd student to meet, the 2nd student need to arrive when 1st student is still arround, therefore the probability that 2nd student arrives when 1st student is arround = 7/32
*If 2nd student arrives before 1st student, the probability that they would meet is 7/32
* Adding both together 7/32 + 7/32 = 7/16
ANSWER = 0.4375
=0.44
