3 years ago

If the area of a square field is 39.69 sq.m, find the length of one side. plz it urgent

Mathematics

2 answers:

olga2289 [7]3 years ago

8 0

Answer:

yhfyugcg

Step-by-step explanation:

ghuihhjjfi night ighi

Gennadij [26K]3 years ago

4 0

Answer:

6.3 m

Step-by-step explanation:

Area = side²

39.69 = s²

s = 6.3 m

You might be interested in

Subtract: (4n + 7) - (7n - 8)

Furkat [3]

4n+7−(7n−8)

=4n+7+−1(7n−8)

=4n+7+−1(7n)+(−1)(−8)

=4n+7+−7n+8

Combine Like Terms

=4n+7+−7n+8

=(4n+−7n)+(7+8)

=−3n+15

4 0

3 years ago

Which best describes her prediction?

ohaa [14]

There is no picture or anything but it’s ok .

3 0

3 years ago

What is 2+2? I NEED HELP ASAP!

FromTheMoon [43]

Answer:

Step-by-step

dam its so simple it hurts my brain

8 0

3 years ago

Simplify the following expression. cot^2x secx-cosx

Solnce55 [7]

ANSWER

$\cos(x) \cot ^{2} (x)$

EXPLANATION

The given expression is;

$\cot^{2} (x) \sec(x) - \cos(x)$

Change everything to

$\sin(x)$

and

$\cos(x)$

This implies that,

$\frac{ \cos^{2} (x) }{ \sin^{2} (x) } \times ( \frac{1}{ \cos(x) } )- \cos(x)$

Cancel the common factors,

$\frac{ \cos(x) }{ \sin^{2} (x) } \times ( \frac{1}{1} )- \cos(x)$

$\frac{ \cos(x) }{ \sin^{2} (x) }- \cos(x)$

$\frac{ \cos(x) - \sin ^{2} (x) \cos(x) }{ \sin^{2} (x) }$

$= \frac{ \cos(x)(1 - \sin ^{2} (x) ) }{ \sin^{2} (x) }$

$= \frac{ \cos(x)(\cos^{2} (x) ) }{ \sin^{2} (x) }$

$= \cos(x) \cot^{2} (x)$

6 0

2 years ago

Five friends split a $65.20 bill at a restaurant they also each left $2.75 for the tip how much money did each person pay in all

Deffense [45]

Each friend payed $15.79!

5 0

3 years ago