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3 years ago

Solve the following equation 1/x-1+1/x+2=3

Mathematics

1 answer:

disa [49]3 years ago

6 0

Answer:

x = 1

Step-by-step explanation:

Solve for x over the real numbers:

-1 + 2 + 1/x + 1/x = 3

-1 + 2 + 1/x + 1/x = 1 + 2/x:

1 + 2/x = 3

Bring 1 + 2/x together using the common denominator x:

(x + 2)/x = 3

Multiply both sides by x:

x + 2 = 3 x

Subtract 3 x + 2 from both sides:

-2 x = -2

Divide both sides by -2:

Answer: x = 1

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Help on math problem

Anvisha [2.4K]

Das is similarity

the 2 triangles are similar because of math ( don't remember which theorem or whatever)

so since similar

we have to find the bottom length
use right triangle properties
a²+b²=c²
14²+5.5²=c²
196+30.25=c²
226.25=c²
√226.25=c

ten, we do similarity

the hyptonuse of smaller triangle to base of smaller triangle is √226.25:5.5
since the triangles are similar, that should be equal to the ratio of the hypotonuse of the largger triangle to the base, which is x:√226.25

so
x/√226.25=√226.25/5.5
times both sides by √226.25
x=226.25/5.5
x≈41.1363636

the height of screen is 6 less than total
41.13636-6=35.13636

height of screen is about 35ft

5 0

3 years ago

Person to get this question right will get brainliest: If I have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 li

dybincka [34]

Answer:

If i have three moles of a gas at a pressure of 5.6 atm and a volume of 3 liters, what is the temperature ?

We have the following data:

n (number of moles) = 3 moles

P (pressure) = 5.6 atm

V (volume) = 12 L

T (temperature) = ? (in Kelvin)

R (gas constant) = 0.082 atm.L / mol.K

We apply the data above to the Clapeyron equation (gas equation), let's see:

Answer:

The temperature is approximately 205 Kelvin

5 0

3 years ago

Read 2 more answers

Please help soon! Unit test :P

fgiga [73]

Answer: 3(25%) + 10% OPTION B. Can I get brainliest pls :)

4 0

3 years ago

Porfabor necesito ayuda en la esta pregunta. ¿Encuentra cuatro pares ordenados de la siguiente función? f(x) = X3 – 2X2 – 2

zlopas [31]

Answer:

(0, -2), (1, -3), (2, -2) y (3, 7) son pares ordenados de $f(x) = x^{3}-2\cdot x^{2}-2$ .

Step-by-step explanation:

Un par ordenado es un elemento de la forma $(x,f(x))$ , donde $x$ es un elemento del dominio de la función, mientras $f(x)$ es la imagen de la función evaluada en $x$ . Entonces, un par ordenado que está contenido en la citada función debe satisfacer la siguiente condición:

La imagen de la función existe para un elemento dado del dominio. Esto es:

$x \rightarrow f(x)$

Dado que $f(x)$ es una función polinómica, existe una imagen para todo elemento $x$ . Ahora, se eligen elementos arbitrarios del dominio para determinar sus imágenes respectivas:

x = 0

$f(0) = 0^{3}-2\cdot (0)^{2}-2$