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3 years ago

Use properties of addition and subtraction to evaluate the expression. −24−8−26 Enter your answer in the comments below.

Mathematics

1 answer:

Sav [38]3 years ago

6 0

The answer to this would be -58

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Greatest common factor for 28y^7x^4u^3 and 8x^4u^5

Nataly [62]

Answer:

Step-by-step explanation:

$28y^{7} *x^{4} *u^{3} \\8x^{4} *u^{5}$

rewrite those 2 terms to better see what they have in common

$4*7 *x^{4} *u^{3} *y^{7} \\4*2*x^{4}*u^{3} *u^{2}$

because, 4*7 =28, 4*2=8, u³*u² =u^5, and multiplication is commutative

The greatest common factor is:

$4x^{4} u^{3}$

3 0

3 years ago

Megan ate 3/4 of a cookie write an equivalent fraction for the amount of cookie megan did not eat

dexar [7]

Subtract what Megan ate from the whole.
4/4-3/4 = 1/4.
Megan did not eat 1/4th of the cookie

4 0

3 years ago

Diane has pizza for making pizzas. She separates the dough into the three portions listed below. Portion a is 8.25 ounces. Porti

SSSSS [86.1K]

Answer:

portion b is 17 ounces. portion c is 34 ounces.

Step-by-step explanation:

portion a is 8.25 ounces and since portion bis twice that amount u multiply 8.25 by 2 and u get 17, that is portion b. portion c is twice portion b which means u have to multiply 17 by 2 which is 34, which makes portin c 34 ounces.

7 0

3 years ago

Read 2 more answers

fladli sells televisions. He earns a fixed amount for each television and an additional $ 20 if the buyer gets an extended warra

ivanzaharov [21]

Answer: $80

Step-by-step explanation:

Given: The amount earned by Fadil on selling 14 televisions= $1400

Therefore, the amount he earned on selling 1 television= $\frac{1400}{14}=\$100$

Since, he sold televisions with extended warranty and he earns $20 additional for it.

Then, the fixed amount Fadil earns for each television= $\$100-\$20=\$80$

Hence, Fadil earns $80 as the fixed amount for each televison.

4 0

4 years ago

Find the possible values for s in the inequality 12s – 20 ≤ 50 – 3s – 25.

Margaret [11]

◆ INEQUALITIES ◆

$given \: expression \: \: - \\ \\ 12s - 20 \leqslant 50 - 3s - 25 \\ \\ 12s - 20 \leqslant 25 - 3s \\ \\ adding \: 20 \: both \: sides \: \: , \: \\ we \: get \: - \\ \\ 12 s \leqslant 45 - 3s \\ \\ 12s + 3s \leqslant 45 \\ \\ 15s \leqslant 45 \\ s \leqslant \frac{45}{15} \\ \\ \\ s \leqslant 3 \: \: \: \: \: \: ans.$

8 0

3 years ago