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3 years ago

What is another way to name line l? need help asap

Mathematics

2 answers:

kkurt [141]3 years ago

6 0

Answer:

you can name it a or b like any letters

harkovskaia [24]3 years ago

5 0

Answer:line AM

Step-by-step explanation:Since AM is a line, it does not have a starting or an ending point.It also passes through l.

Please mark my answer as Brainliest

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"6. A brand name has a 40% recognition rate. Assume the owner of the brand wants to verify that rate by beginning with a small s

statuscvo [17]

Answer:

(a) The probability that exactly 5 of the 6 consumers recognize the brand name is 0.0369.

(b) The probability that all of the selected consumers recognize the brand name is 0.0041.

(d) The events of 5 customers recognizing the brand name is unusual.

Step-by-step explanation:

Let X = number of consumer's who recognize the brand.

The probability of the random variable X is, P (X) = p = 0.40.

A random sample of size, n = 6 consumers are selected.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

(a)

Compute the value of P (X = 5) as follows:

$P(X=5)={6\choose 5}0.40^{5}(1-0.40)^{6-5}\\=6\times0.01024\times0.60\\=0.036864\\\approx0.0369$

Thus, the probability that exactly 5 of the 6 consumers recognize the brand name is 0.0369.

(b)

Compute the value of P (X = 6) as follows:

$P(X=6)={6\choose 6}0.40^{6}(1-0.40)^{6-6}\\=1\times 0.004096\times1\\=0.004096\\\approx0.0041$

Thus, the probability that all of the selected consumers recognize the brand name is 0.0041.

(c)

Compute the value of P (X ≥ 5) as follows:

P (X ≥ 5) = P (X = 5) + P (X = 6)

= 0.0369 + 0.0041

= 0.041

Thus, the probability that at least 5 of the selected consumers recognize the brand name is 0.041.

(d)

An event is considered unusual if the probability of its occurrence is less than 0.05.

The probability of 5 customers recognizing the brand name is 0.0369.

This probability value is less than 0.05.

Thus, the events of 5 customers recognizing the brand name is unusual.

8 0

4 years ago

Which situation could be represented by an exponential function select each correct answer

ANTONII [103]

Answer:

The first and third options are the examples of exponential functions.

Step-by-step explanation:

When a quantity is compounded after a certain interval of time at a certain rate, then we can assume that the situation can be represented by an exponential function.

In the first option: An event organizer finds each year's attendance for the past five years is about $\frac{4}{5}$ of previous year's attendance.

So, here the total attendance is compounding every year by a factor $\frac{4}{5}$ of previous year's attendance.

Again, in the third case: The total population is increasing by about 7.5% each year.

Hence, the population is compounded every year by 7.5% of the previous year's population.

Therefore, the first and third options are examples of exponential functions. (Answer)

3 0

3 years ago

Need Help

masya89 [10]

So you subtract $22.89 from $54.73 to get a total of $31.84 and that’s how much the customer paid.

6 0

3 years ago

(please zoom / zoom out if needed to see question. (: )

Semmy [17]

A circle is 360° all the way around; therefore, if you divide an arc's degree measure by 360°, you find the fraction of the circle's circumference that the arc makes up. Then, if you multiply the length all the way around the circle (the circle's circumference) by that fraction, you get the length along the arc.

8 0

3 years ago

Determine the value of w and x in the figure below. (Thanks for the help I really appreciate it!)

storchak [24]

Triangle HAM looks like an isosceles triangle, and we know that in an isosceles triangle 2 of the angles are the same.

so :
180 - 106 = 74 ( sum of the other 2 angles )
74/2 = 37 ( sum of angle HMA / HAM )

angles on a straight line add up to 180.
180-37=143 ( angle x )

since triangle YMH is also an isosceles,
180-37=143
143/2=71.5 ( angle w )

7 0

3 years ago