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Mice21 [21]
3 years ago
8

Less than 0 and greater than -10

Mathematics
2 answers:
Veronika [31]3 years ago
7 0

Answer:

-5

Step-by-step explanation:

vesna_86 [32]3 years ago
5 0

Answer:

<u />

<u>see the explanation</u>

Step-by-step explanation:

I dont understand what you want here

here are the numbers which satisfy this statement

-1,-2,-3,-4,-5,-6,-7,-8,-9

here is the inequality

0>x>-10

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Please solve for w, p=21+2w
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Answer:

w = (p - 21)/2

Step-by-step explanation:

Rearrange the equation so that it is equal to w.

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Step-by-step explanation:

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13.......................
Alla [95]

Answer:

The answer is (d) ⇒ pq^{2}r\sqrt[3]{pr^{2}}

Step-by-step explanation:

* To simplify the cube roots:

 If its number then the number must be written in the form x³

 then we divide the power by 3 to cancel the radical

 If its variable we divide its power by 3 to cancel the radical

∵ \sqrt[3]{p^{4}q^{6}r^{5}}=p^{\frac{4}{3}}q^{\frac{6}{3}}r^{\frac{5}{3}}}

∴ p^{\frac{4}{3}}q^{2}}r^{\frac{5}{3}}=p^{1\frac{1}{3}}q^{2}r^{1\frac{2}{3}}

∵ p^{\frac{1}{3}}=\sqrt[3]{p}

∵ r^{\frac{2}{3}}=\sqrt[3]{r^{2}}

∴ p(p)^{\frac{1}{3}}q^{2}r(r)^{\frac{2}{3}}=p(\sqrt[3]{p})q^{2}r(\sqrt[3]{r^{2}})

∴ prq^{2}\sqrt[3]{pr^{2}}}

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