What is the value of s in the equation 3r = 10 + 5s, when r = 10

1 answer:

8 0

3r = 10 + 5s , r = 10
plug in the value of "r" into the equation:
3(10) = 10 +5s
30 = 10 + 5s
subtract 10 from both sides:
20 = 5s
divide both sides by 5:
4 = s
s = 4

You might be interested in

If PQ=8 and Q lies at -13 where could P be located?

choli [55]

Answer:

In the given figure the point on segment PQ is twice as from P as from Q is. What is the point? Ans is (2,1).

Step-by-step explanation:

There is really no need to use any quadratics or roots.

( Consider the same problem on the plain number line first. )

How do you find the number between 2 and 5 which is twice as far from 2 as from 5?

You take their difference, which is 3. Now splitting this distance by ratio 2:1 means the first distance is two thirds, the second is one third, so we get

4=2+23(5−2)

It works completely the same with geometric points (using vector operations), just linear interpolation: Call the result R, then

R=P+23(Q−P)

so in your case we get

R=(0,−1)+23(3,3)=(2,1)

Why does this work for 2D-distances as well, even if there seem to be roots involved? Because vector length behaves linearly after all! (meaning |t⋅a⃗ |=t|a⃗ | for any positive scalar t)

Edit: We'll try to divide a distance s into parts a and b such that a is twice as long as b. So it's a=2b and we get

s=a+b=2b+b=3b

⇔b=13s⇒a=23s

7 0

2 years ago

10 + (2^2 + 3^2) x 2 PEMDAS

yarga [219]

The answer would be 36.

Following PEMDAS, you'd solve what's in the parenthesis first. 2^2 = 4 and 3^2 = 9. This leaves you with 10 + (4 + 9) x 2. Add 9 and 4 to get 13, and then the parenthesis are done.

Next, you'd multiple 13 and 2 (since it's the next step in PEMDAS) to get 26.

Finally, you add together 10 and 26 to get the answer, which is 36.

I hope this helps!

3 0

3 years ago

Read 2 more answers

A ball is thrown vertically upward from the top of a building 160 feet tall with an initial velocity of 48 feet per second. The

alina1380 [7]

Answer:

# after 5 seconds, the ball strikes the ground

# The ball reaches maximum height at t = 1.5 seconds

# The max height is 196 feet

Step-by-step explanation:

The equation is:

$d(t)=-16t^2+48t+160$