Answer:
90°
Step-by-step explanation:
Actually the question should be AC is tangent to circle B at point C. What is the measure of angle BCA.
AC is tangent and BC is radius.
Radius is perpendicular to the tangent.
Therefore,
measure of angle BCA = 90°
Answer:
31
Step-by-step explanation:
Answer:
x = plus or minus √7
Step-by-step explanation:
Solve the equation 7x^2=49, starting out by dividing both sides by 7. This results in x^2 = 7.
We need to solve for (isolate) x. To do this, take the square root of both sides:
x = plus or minus √7
Answer:
200 trucks
Step-by-step explanation:
There's about 15 trucks in the 2nd row from the right. It looks to be about 1/2 the size of the rows to the left of it.
So based on that, I can assume, there are about 30 trucks in each of the 5 long rows, and both of the short rows would make up about another 30 trucks total. There are various trucks parked along the perimeter or between rows, so I estimated there would be about 20 of those based on 3 per row.
30 x 5 = 150 +30 = 180 + 20 = 200
Answer:
(a) 8 balls
(b) 4 balls
Step-by-step explanation:
Let
Number of balls
For a box, the probability that there are N balls in it is:
![Pr = 0.5^N](https://tex.z-dn.net/?f=Pr%20%3D%200.5%5EN)
For 2 boxes, it is:
![Pr = 2 * 0.5^N](https://tex.z-dn.net/?f=Pr%20%3D%202%20%2A%200.5%5EN)
From the question, we have:
Favorable outcome
To solve for N, we have:
![2 * 0.5^N = \frac{80}{10000}](https://tex.z-dn.net/?f=2%20%2A%200.5%5EN%20%3D%20%5Cfrac%7B80%7D%7B10000%7D)
![2 * 0.5^N = 0.008](https://tex.z-dn.net/?f=2%20%2A%200.5%5EN%20%3D%200.008)
Divide both sides by 2
![0.5^N = 0.004](https://tex.z-dn.net/?f=0.5%5EN%20%3D%200.004)
Take log of both sides
![\log(0.5^N) = \log(0.004)](https://tex.z-dn.net/?f=%5Clog%280.5%5EN%29%20%3D%20%5Clog%280.004%29)
Apply law of logarithm
![N\log(0.5) = \log(0.004)](https://tex.z-dn.net/?f=N%5Clog%280.5%29%20%3D%20%5Clog%280.004%29)
Make N the subject
![N = \frac{\log(0.004)}{\log(0.5)}](https://tex.z-dn.net/?f=N%20%3D%20%5Cfrac%7B%5Clog%280.004%29%7D%7B%5Clog%280.5%29%7D)
![N =7.966](https://tex.z-dn.net/?f=N%20%3D7.966)
Approximate
![N = 8](https://tex.z-dn.net/?f=N%20%3D%208)
Solving (b): Balls in one of the two boxes.
Here, we assume that each ball will have almost the same number of balls at a given instance;
Hence, we have:
![Balls \approx \frac{N}{2}](https://tex.z-dn.net/?f=Balls%20%5Capprox%20%5Cfrac%7BN%7D%7B2%7D)
![Balls \approx \frac{8}{2}](https://tex.z-dn.net/?f=Balls%20%5Capprox%20%5Cfrac%7B8%7D%7B2%7D)
![Balls \approx 4](https://tex.z-dn.net/?f=Balls%20%5Capprox%204)
<em>4 balls in each box</em>