May someone help me on this please

Pls help me with this

Valentin [98]

Answer:

24

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Oh mah lord please please help me

Alenkinab [10]

Option 2: $4^{\frac{1}{6}}$ is the correct answer.

Step-by-step explanation:

The radical expressions like these are simplified by using fractional exponents

given

$\frac{\sqrt{4}}{\sqrt[3]{4} }$

Converting radicals into exponents

When there is no base the exponent is 1/2 and as the base is 3, the exponent will be 1/3

So

$=\frac{4^{\frac{1}{2}}}{4^{\frac{1}{3}}}$

As the bases of numerator and denominator is same, the exponents can be subtracted

$=4^{\frac{1}{2}-\frac{1}{3}}\\=4^{\frac{3-2}{6}}\\=4^{\frac{1}{6}}$

Hence,

Option 2: $4^{\frac{1}{6}}$ is the correct answer.

Keywords: Exponents, radicals

Learn more about radicals at:

#LearnwithBrainly

7 0

3 years ago

Find the value of k for which the line y = kx + 6 is a tangent to the curve x^2 + y^2 – 10x + 8y = 84

guajiro [1.7K]

Answer:

k = 1/2

Step-by-step explanation:

input y = kx +6 into the equation of the curve x² + y² – 10x + 8y = 84

x² + (kx + 6)² - 10x + 8(kx + 6) = 84

expand:

x² + k²x² + 12kx + 36 - 10x + 8kx + 48 = 84

simplify by collecting like terms:

x² + k²x² + 20kx - 10x + 84 = 84

subtract 84 on both sides to bring it to the left:

x² + k²x² + 20kx - 10x + 84 - 84 = 0

x² + k²x² + 20kx - 10x = 0

factorise out x:

x²(1 + k²) + x(20k - 10) = 0

using the discriminant b² - 4ac where b is 20k - 10, a is 1 + k² and c is 0, substitute them in the formula b² - 4ac:

b² - 4ac

(20k - 10)² - 4(1 + k²)(0) = 0

the part highlighted in bold is gone because it's all multiplied by 0, so we are left with (20k - 10)² = 0

(20k - 10)² is the same as

(20k - 10)(20k - 10)

equate both to 0

20k - 10 = 0 and 20k - 10 = 0

add 10 on both sides

20k = 10 and 20k = 10

divide 20 on both sides

k = 10/20 and k = 10/20 which are both the same

10/20 is simplified to 1/2

k = 1/2

5 0

2 years ago

Consider two functions: g(x)=−x2−6x and the quadratic function f(x) shown in the table.

S_A_V [24]

Answer:

Hence average rate of change is greater for f(x) in (0,3).

Yes. f(x) is greater than g(x) in the interval (0,3)

Yes. g(3) <f(3)

Step-by-step explanation:

To find average rate of change of f and g in (0,3)

f(3)-f(0)/3 = (9-0)/3 =3

g(3) = -9-18 = -27

g(0) = 0

Rate of change in(0,3) of g(x) = -27/3 =-9

Hence average rate of change is greater for f(x) in (0,3)

---

Both f and g have intercepts of y as 0

Hence both are equal.

3) Yes. f(x) is greater than g(x) in the interval (0,3)

Because g(x) <0 for all x in (0,3) while f(x) >0

4) g(3)= -9-18=-27 <f(3)

5 0

3 years ago

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4. Calculate the product of 8/15, 6/5, and 1/3.

RSB [31]

A because the 6 and 3 cancel out
Then 2 x 8 is (16) and 15 x 5 is (75)
Making it A

6 0

3 years ago

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