The correct answer is B). 6
Radius of inscribed circle of triangle HJK is 6 unit
Step-by-step explanation:
As shown in figure,
The triangle HJK has In-circle or inscribed circle of radius PL(or PM or PN)
Since, PL and PM is radius of same in-circle,
PL = PM
Given that PL=3x+4 and PM =6x-14
3x+4=6x-14
3x=18
x=6
Thus, The correct answer is B). 6
Both lines are parallel so using the bottom line you are given angle 7 as being 80 degrees. Angle 5 and 7 form a straight line which is 180 degrees so angle 5 would be 180-80 = 100 degrees.
Angle 1 is the same as angle 5 so angle 1 is 100 degrees.
Answer: 100 degrees
Answer:
Cole has 15 pencils.
Step-by-step explanation:
First, we have the equation c + o =18, c representing cole, and o representing connor.
From there, we get 5o=c
Using substitiution, we get o=3
5(3)=15
15+3=18
Answer
Arc EF = 52°
Arc HD = 142°
Angle HGF = 128°
Explanation
To solve for the unknown angles, we need to first solve for x
To do that, we need to first note that the sum of angles on a straight line is 180°
So,
Angle HCG + Angle HCD = 180° (Sum of angles on a straight line)
Angle HCG = 2x
Angle HCD = 6x + 28°
Angle HCG + Angle HCD = 180°
2x + 6x + 28° = 180°
8x + 28° = 180°
8x = 180° - 28°
8x = 152°
Divide both sides by 8
(8x/8) = (152°/8)
x = 19°
Angle HCG = 2x = 2 (19°) = 38°
Angle HCD = 6x + 28° = 6(19°) + 28° = 142°
So, we can solve for the rest now
Arc EF = Angle ECF
= 90° - Angle ECD
Angle ECD = Angle HCG = 38° (Vertically opposite angles are equal)
Arc EF = Angle ECF
= 90° - Angle ECD
= 90° - 38°
= 52°
Arc HD = Angle HCD = 142°
Angle HGF = Angle HCG + Angle GCF = 38° + 90° = 128°
Hope this Helps!!!
Answer:
And we can find this probability using the normal standard table or excel:
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the amount of ml of a population, and for this case we know the distribution for X is given by:
Where 
and 
We are interested on this probability
And the best way to solve this problem is using the normal standard distribution and the z score given by:
If we apply this formula to our probability we got this:
And we can find this probability using the normal standard table or excel:
