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forsale [732]
3 years ago
10

What is 1 minus 1 over 2

Mathematics
2 answers:
Ad libitum [116K]3 years ago
6 0
1-1/2

is  .50 becasue you are taking 1 from the 1 half

hope this helps :) 
Reika [66]3 years ago
3 0
1-1 is 2. 2 over 2 is the same as 1.
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Find the distance between 6.2 and<br> -4.3 on a number line.
Nitella [24]

Answer:

The two given numbers are 10.5 units apart.

Step-by-step explanation:

Subtract the smaller from the larger.  The larger number here is 6.2. Then we have

6.2 - (-4.3) = 6.2 + 4.3 = 10.5

The two given numbers are 10.5 units apart.

8 0
3 years ago
CAN SOMONE ANSWER THIS
laiz [17]

Your answer is 8,000 minus 6 & 4

Step-by-step explanation:

3 0
3 years ago
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At the local pet store, zebra fish cost $2.00 each and neon tetras cost $2.15 each. If Ernesto bought 15 fish for a total cost o
bezimeni [28]
So first create and define your variables:
Z = amount of zebra fish
N = amount of neon tetras

Now create your equations:
2z+2.15n=31.20
z+n=15
This is your system. There are multiple methods to use but in this problem I’ll use the substitution method by simplifying the bottom equation.
2z+2.15n=31.20
z=15-n
Now I’ll plug the bottom equation into the top one.
2(15-n)+2.15n=31.20
And just solve from here.
30-2n+2.15n=31.20
0.15n=1.20
n=8
So he bout 8 neon tetras, and 15-8= 7, so he bought 7 zebra fish
6 0
3 years ago
Read 2 more answers
Y is a random variable that is distributed N(-16, 1.21). Find k such that Prob(-15.043 &lt; Y ≤ k) = 0.1546. (Round your answer
IgorLugansk [536]

Transform <em>Y</em> to <em>Z</em>, which is distributed N(0, 1), using the formula

<em>Y</em> = <em>µ</em> + <em>σZ</em>

where <em>µ</em> = -16 and <em>σ</em> = 1.21.

Pr[-15.043 < <em>Y</em> ≤ <em>k</em>] = 0.1546

Pr[(-15.043 + 16)/1.21 < (<em>Y</em> + 16)/1.21 ≤ (<em>k</em> + 16)/1.21] = 0.1546

Pr[0.791 < <em>Z</em> ≤ (<em>k</em> + 16)/1.21] ≈ 0.1546

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] - Pr[<em>Z</em> < 0.791] = 0.1546

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] = 0.1546 + Pr[<em>Z</em> < 0.791]

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] ≈ 0.1546 + 0.786

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] ≈ 0.940

Take the inverse CDF of both sides (<em>Φ(x)</em> denotes the CDF itself):

(<em>k</em> + 16)/1.21 ≈ <em>Φ⁻¹</em> (0.940) ≈ 1.556

Solve for <em>k</em> :

<em>k</em> + 16 = 1.21 • 1.556

<em>k</em> ≈ -14.118

8 0
3 years ago
Solve for X: -2(x+3)=-2(x+1)-4
vodomira [7]

Answer:

All real numbers are solutions.

Step-by-step explanation:

3 0
3 years ago
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