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svet-max [94.6K]
3 years ago
7

Round both numbers to find the answer-WRITE OUT THE NEW PROBLEM 89 x 32

Mathematics
2 answers:
JulijaS [17]3 years ago
7 0

Answer:

i agrre with the person on top the answer is 2848

ankoles [38]3 years ago
5 0

Answer:

2848

Step-by-step explanation:

89 x 32 = 2848

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HELP ME!!! ITS DUE TOMMOROW!! Find the largest value of $r$ such that $6r^2+7r+8=6$.
Alex787 [66]
First you need to see that this is a quadratic. I need.to put all of the values on one side of equation to see what I got.
6r^2 + 7r + 8 = 6
6r^2 + 7r + 2 = 0

Now this one is difficult to factor so i will use quadratic equation:
[-b (+-) sqrt (b^2 - 4ac)] / (2a)

we know that a b and c are in a quadratic at these positions.
ax^2 + bx + c

so
[-7 (+-) sqrt (7^2 -(4)(6)(2)] / (2) (6)
[-7 (+-) sqrt (49 - 48)] / 12
[-7 (+-) 1] /12

split into the + and - for 2 answers
(-7 + 1) / 12
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And
(-7 -1) /12
-8 / 12
-2/3

those are.the 2 answers

But but it says largest so -1/2
4 0
3 years ago
Read 2 more answers
How many years (approximately) will it take $6,000 to amount $8,000 if it is invested at an annual rate of 9.0% compounded conti
quester [9]

Answer:

It should take roughly 3.5 years

Step-by-step explanation:


6 0
3 years ago
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The following data gives the speeds (in mph), as measured by radar, of 10 cars traveling north on I-15. 76 72 80 68 76 74 71 78
____ [38]

Answer:

71.123 mph ≤ μ ≤ 77.277 mph

Step-by-step explanation:

Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:

m-t_{a/2,n-1}\frac{s}{\sqrt{n} } ≤ μ ≤ m+t_{a/2,n-1}\frac{s}{\sqrt{n} }

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the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.

So, if we replace m by 74.2, s by 5.3083, n by 10 and t_{0.05,9} by 1.8331, we get that the 90% confidence interval for the mean speed is:

74.2-(1.8331)\frac{5.3083}{\sqrt{10} } ≤ μ ≤ 74.2+(1.8331)\frac{5.3083}{\sqrt{10} }

74.2 - 3.077 ≤ μ ≤ 74.2 + 3.077

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8 0
3 years ago
I forgot how to do this. Please help!
Annette [7]

Answer:Here

I forgot how to do this. Please help!

Step-by-step explanation:

5 0
3 years ago
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Profit:p=r-c;solve for c
eduard
If you would like to solve p = r - c for c, you can do this using the following steps:

p = r - c         /+c
p + c = r - c + c
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p + c - p = r - p
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The correct result would be c = r - p.
5 0
3 years ago
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