The measure of Arc Q P is 96°. We also know that ∠QTP is central angle, then the measure of arc QP is 96°.
Step-by-step explanation:
<u>Step 1</u>
If QS is a circle diameter,
then m∠QTS=180°.
Let x be the measure of angle RTQ: ∠RTQ =x.
so, let ∠RTQ = x
<u />
<u>Step 2</u>
According to the question,
∠RTQ = ∠RTS - 12°
⇒ ∠RTS = x + 12°
∴ ∠QTS = ∠RTQ + ∠RTS
= x + x + 12° = 2x + 12° = 180°
⇒ 2x = 168°
⇒ x = 84°
⇒ ∠RTQ = 84°
<u></u>
<u>Step 3</u>
Now,
∵∠QTP and ∠RTS are vertical angles
∴ ∠QTP = 84° + 12° = 96°
As ∠QTP is the central angle, hence the measure of arc QP is 96°
<u></u>
<u>Step 4</u>
The Measure of arc QP = 96°
Answer:
g(2) = 2
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given that 
Put x =2
= -1+3
= 2
g(2) = 2
Answer:
6,5
Step-by-step explanation:
-2 is 4 down from 2, so reflected should be 4 up, or 6
- two acute angle=<JBC and <JBG
<JBC and <JBG(because these two angle are 45°)
by definition of acute angle any angle which is between 0°to 90° then it will acute angle
- two straight line=FH ,.AD
- two right angle=<GBD and <GBA
- two obtuse angle=<BCH and <BGF
