A. The translation rule is (x , y) → (x - 2 , y + 6)
B. The coordinates of the vertices of the image are A' (-11 , 12) , B' (-6 , 0) , C' (-5 , 8) , D' (-5 , 4)
Step-by-step explanation:
Let us revise the translation of a point
- If the point (x , y) translated horizontally to the right by h units then its image is (x + h , y)
- If the point (x , y) translated horizontally to the left by h units then its image is (x - h , y)
- If the point (x , y) translated vertically up by k units then its image is (x , y + k)
- If the point (x , y) translated vertically down by k units then its image is (x , y - k)
A.
∵ Quadrilateral ABCD is translated to the left 2 units and up 6 units
- That means subtract 2 from each x-coordinates and add 6
to each y-coordinates
∵ (x , y) is moved to the left 2 units ad up 6 units
∴ Its image is (x - 2 , y + 6)
The translation rule is (x , y) → (x - 2 , y + 6)
B.
∵ The vertices of the quadrilateral ABCD are
A (-9 , 6) , B (-4 , -6) , C (-3 , 2) , D (-3 , -2)
∵ Quadrilateral ABCD is translated to the left 2 units and up 6 units
- Use the rule in part A to find the image of each vertex
∵ A' = (-9 - 2 , 6 + 6)
∴ A' = (-11 , 12)
∵ B' = (-4 - 2 , -6 + 6)
∴ B' = (-6 , 0)
∵ C' = (-3 - 2 , 2 + 6)
∴ C' = (-5 , 8)
∵ D' = (-3 - 2 , -2 + 6)
∴ D' = (-5 , 4)
The coordinates of the vertices of the image are A' (-11 , 12) , B' (-6 , 0) , C' (-5 , 8) , D' (-5 , 4)
Learn more:
You can learn more about the translation in brainly.com/question/2451812
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