What are the x- and y-intercepts of the graph of y = x2 − 10x + 21?
2 answers:
To solve for the X intercepts make y equal to 0. Then factor the quadratic. It would become (X-7)(X-3)=0. Solve for x in each case and the X intercepts are (3,0) and (7,0). The y intercept can be determined by making the X variables in the above quadratic equal to 0. The y intercept is 21, or (0,21).
Answer:
y intercepts: y = 21
x intercepts: x = 3 and x = 7
Step-by-step explanation:
The given graph is y = x² - 10x + 21
We have to find the x and y intercepts of the given graph.
Since we know for x- intercepts we equate y = 0 and for y-intercepts we put x = 0
Now for x-intercepts
x² - 10x + 21 = 0
x² - 7x - 3x + 21 = 0
x(x - 7) - 3(x - 7) = 0
(x - 3)(x - 7) = 0
x - 7 = 0
x = 7
Or x - 3 = 0
x = 3
Therefore, there are two x intercepts x = 3 and x = 7
Now for y-intercepts
y = 0 - 0 + 21
y = 21
Therefore, x intercepts are; x = 3 and x = 7 and y intercept is y = 21
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1261.68
Step-by-step explanation:
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1261.68224299
Check:
7% of 1261.68224299 is 88.317757
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Round:
1261.68224299
To the penny= to the hundreth= 1261.68
Answer:
b = 55°
c = 35°
Step-by-step explanation:
b° = 180° - (85°+40°) = 180° - 125° = 55°
c° = 180° - (b°+90°) = 180° - (55°+90°) = 180° - 145° = 35°
<em>f(3) = 13</em>
Step-by-step explanation: <em>f(x) = 2x + 7</em>
<em>replace </em><em>x </em><em> with </em><em>3 </em>
<em>f(3) = 2×3 + 7</em>
<em>= 6 + 7</em>
<em>= 13</em>
I have attached an image of the process I used
-64, -50, -45, 28, 34, 65