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3 years ago

Which step should be used to prove that point A is equidistant from points C and B

1 answer:

5 0

You have to prove that point A is the midpoint of the line segment CB and that will rove that it is equidistant from points c and b

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winthrop Middle School had enrollment of 1,342 and a total of 215 teachers. what was the student teacher ratio for this School w

eimsori [14]

Teachers= 215
Students= 1,342

Student: Techer
= 1,342: 215
= 62.1:1
= $\frac{62.1}{1}$

3 0

2 years ago

Read 2 more answers

A personnel manager is concerned about absenteeism. She decides to sample employee records to determine if absenteeism is distri

nlexa [21]

Answer:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

For this case we want to test:

H0: Absenteeism is distributed evenly throughout the week

H1: Absenteeism is NOT distributed evenly throughout the week

We have the following data:

Monday Tuesday Wednesday Thursday Friday Saturday Total

12 9 11 10 9 9 60

The level of significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{60}{6}= 10$ and the expected value is the same for all the days since that's what we want to test.

now we can calculate the statistic:

$\chi^2 = \frac{(12-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(11-10)^2}{10}+\frac{(10-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(9-10)^2}{10}=0.8$

Now we can calculate the degrees of freedom (We know that we have 6 categories since we have information for 6 different days) for the statistic given by:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

4 0

2 years ago

A geologist in South America discovers a bird skeleton that contains 80% of its original amount of C-14. N0= initial amont of C-

kap26 [50]

A geologist in South America discovers a bird skeleton that contains 80% of its original amount of C-14

We use formula $N = N_oe^{-kt}$

N0= initial amont of C-14 (at time t=0)

N= amount of C-14 at time t

t= time, in years

k= 0.0001

N is 80% of N0 that is $N= 0.80N_o$

$N = N_oe^{-kt}$

$0.80N_o = N_oe^{-kt}$

Divide both sides by N_o

$0.8=e^{-0.0001 t}$

Take ln on both sides

$ln(0.8)=lne^{-0.0001 t}$

ln(0.8) = -0.0001t ln(e)

ln(0.8) = -0.0001t

Divide both sides by -0.001

t = 2231.435513

The age of the bird skeleton is 2231 years old

5 0

3 years ago

Can someone help me on this pls? It’s urgent, so ASAP (it’s geometry)

Naddik [55]

Given the parameters in the diagrams, we have;

4. ∆ABC ≈ ∆DEF by ASA

5. UW ≈ XZ by CPCTC

6. QR ≈ TR by CPCTC

<h3>How can the relationship between the triangles be proven?</h3>

4. The given parameters are;

<B = <E = 90°

AB = DE Definition of congruency

<A = <D Definition of congruency

Therefore;

∆ABC ≈ ∆DEF by Angle-Side-Angle, ASA, congruency postulate

5. Given;

XY is perpendicular to WZ

UV is perpendicular to WZ

VW = YZ

<Z = <W

Therefore;

∆UVW ≈ ∆XYZ by Angle-Side-Angle, ASA, congruency postulate

Which gives;

UW is congruent to XZ, UW ≈ XZ, by Corresponding Parts of Congruent Triangles are Congruent, CPCTC

6. Given;

PQ is perpendicular to QT

ST is perpendicular to QT

PQ ≈ ST

From the diagram, we have;

<SRR ≈ <PRQ by vertical angles theorem;

Therefore;

∆QRP ≈ ∆TRS by Side-Angle-Angle, SAA, congruency postulate

Which gives;

QR ≈ TR by Corresponding Parts of Congruent Triangles are Congruent, CPCTC

Learn more about congruency postulates here:

brainly.com/question/26080113

#SPJ1

5 0

1 year ago

Solve the following inequality 0.5z-0.1 >0.2

Paraphin [41]

Answer: z>0.6

Step-by-step explanation:

You isolate the variable by dividing each side by factors that don’t contain the variable.

The answer is verified it came from Math-way .

8 0

3 years ago

Read 2 more answers