Answer:
Step-by-step explanation:
a) The objective of the study is test the claim that the average gain in the green fees , lessons or equipment expenditure for participating golf facilities is less than $2,100 under the claim the null and alternative hypothesis are,
H₀ : μ = $2,100
H₀ : μ < $2,100
B) Suppose you selects α = 0.01
The probability that the null hypothesis is rejected when the average gain is $2,100 is 0.01
C) For α = 0.01
specify the rejection region of a large sample test
At the given level of significance 0.01 and the test is left-tailed then rejection level of a large-sample = < - 1.28
This is a proportion problem.
z 4
--- = ----
12 5
We can cross multiply and divide.
5z = 48
z = 9.6
Hope this helps!
Answer:
212.81
Step-by-step explanation:
212.809 rounded to the nearest hundredth is 212.81
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Statement B describes the relationship
