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Maurinko [17]
3 years ago
10

Find the area of the following trapezoid. 5 7 14​

Mathematics
2 answers:
Triss [41]3 years ago
7 0

Answer:

Welp, you didn't provide a picture so I'll go with every choice.

Step-by-step explanation:

If the two bases are 5 and 7, and the height is 14, then the area is 84.

If the two bases are 5 and 14, and the height is 7, then the area is 66.5.

If the two bases are 7 and 14, and the height is 5, then the area is 52.5.

The formula for the area of a trapezoid is : (a+b)/2 * h

Fynjy0 [20]3 years ago
5 0

Answer:

84

Step-by-step explanation:

5+7 times 14 divided by 2 i think there's no pic

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A circle has the radius of 4 cm. Find the length s of the arc intercepted by a central angle of pie/4 radians.
alexgriva [62]

Answer:

3.1 cm

Step-by-step explanation:

S = r × theta

S = 4 × pi/4

S = pi

S = 3.14 cm

3 0
3 years ago
PLEASE HELP ASAP I WILL GIVE BRAINSLET TO THE CORRECT ANSWER!!!!!!!!!!
cestrela7 [59]

<u>Answer</u>:

Therefore has one solution.

<u>explanation</u>:

Given equations:

6x + y = -7

-24x -7y = 25

Make y the subject:

6x + y = -7

y = -7 - 6x ..............equation 1

-24x -7y = 25

-7y = 25 + 24x

y = (25 + 24x)/-7 ..........equation 2

Solve them simultaneously:

(25 + 24x)/-7 = -7 - 6x

25 + 24x = -7 (-7 - 6x)

25 + 24x = 49 + 42x

42x - 24x = 25- 42

18x = -24

x = -\frac{4}{3}

Then y is:

y = -7 - 6x

y = -7 - 6( -\frac{4}{3})

y = 1

Has one separate value of x and y: (  -\frac{4}{3} , 1 ); so it has one solution.

3 0
2 years ago
A 30 -60 -90 degree triangle has a hypotenuse with a length of 10. What is the length of the longer leg of the triangle?
Degger [83]

Answer:

the right answer is 5√3 believe me i took this quiz

Step-by-step explanation:


6 0
3 years ago
Determine whether the lines are parallel, intersect, or coincide. x-5y=0, y+1=1/5(x+5)
MAXImum [283]

<u>Answer-</u>

<em>The lines are two </em><em>coinciding lines</em><em> or the </em><em>same lines</em><em>.</em>

<u>Solution-</u>

The given line equations are

the first one,

\Rightarrow x-5y=0  

the second one,

\Rightarrow y+1=\dfrac{1}{5}(x+5)\\\\\Rightarrow 5y+5=x+5\\\\\Rightarrow 5y=x\\\\\Rightarrow x-5y=0

As we know two line equations A_1x+B_1y+C_1=0 and A_2x+B_2y+C_2=0 will be,

  1. Parallel if, \dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}
  2. Coincide if, \dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}=\dfrac{C_1}{C_2}
  3. Intersect if, \dfrac{A_1}{A_2}\neq \dfrac{B_1}{B_2}

As here,

\Rightarrow \dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}=\dfrac{C_1}{C_2}

\Rightarrow \dfrac{1}{1}=\dfrac{-5}{-5}

(C₁ and C₂ aren't considered as they are 0)

Therefore, the lines are two coinciding lines or the same lines.

4 0
3 years ago
This recipe makes enough pastry for 10 pasties.
forsale [732]

Answer:

she can only make 25 pastries

Step-by-step explanation:

because 200 fits in 500 only 2.5 and if 1 pastry = 10 pastries then it should be 25 despise the flour that lets us do 30 pastries but we don't have enough butter and there's infinite water soo ye.

You're welcome

6 0
2 years ago
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